Automatic assignment of exam numbers

# Include <iostream>
# Include <vector>
# Include <cstring>
# Include <string>
# Include <iomanip>

Using namespace std;

Typedef struct
{
Int num; // student ID
Char name [20]; // Student name
Char textID [9]; // student admission ticket No.
} Student;
Vector <Student> svec;
Int a3; // use a3 to store the number of test rooms
Int a4; // used to store the number of people in the last unfilled classroom
Const CODE = 18; // The school CODE has been set to 18;
Vector <Student>: iterator iter_begin;

Void input_students_info () // function for inputting Student Information
{
String str;
While (! (Str = "N" | str = "n "))
{

Cout <"/n enter your student ID:" <endl;
Int a1; // enter the student ID.
Cin> a1;
While (a1 <0 | a1> 1000000000)
{
Cout <"the student ID range does not meet the requirements. Please enter it again! "<Endl;
Cin> a1;
Cin. clear ();
}

Cout <"enter your name:" <endl;
Char p1 [20];
Cin. clear ();
Cin> p1;
Cin. clear ();

Student s;
S. num = a1;
Strcpy (s. name, p1 );
Strcpy (s. textID ,"");
Svec. push_back (s );
Cout <"do I need to enter the information of the next candidate? Press (N/n) to end the input, and press any key to continue: "<endl;
Cin> str;

} // While ends

Cout <"the examinee information is entered! "<Endl;
Cout <"Total" <svec. size () <"candidates apply for exams" <endl;
Return;
}

Void produce_text_number ()
{
Int a2; // used to record the maximum number of students per Exam Room
Cout <"Enter the maximum number of students per test room (no more than 30):" <endl;
Cin> a2;
Cin. clear ();
While (! (A2> = 0 & a2 <= 30 ))
{
Cout <"the input does not meet the requirements. Please enter it again! "<Endl;
Cin> a2;
Cin. clear ();
}

If (svec. size () % a2) // if it is not just full, add a test room
{
A3 = svec. size ()/a2 + 1;
A4 = svec. size () % a2;
}

Else a3 = SVEC. Size ()/A2; // the classroom is full.

Iter_begin = SVEC. Begin ();
If (A4! = 0) // when a classroom is not full
{

For (INT I = 1; I <= a3-1; ++ I) // first-installed classroom
{
For (Int J = 1; j <= a2; ++ J, ++ (iter_begin ))
{
Char S1 [9];
Int first = 0, second = 0, oldfirst = 0, oldsecond = 0; // used to find the first two digits of the student ID
S1 [0] = (I/10) + 48;
S1 [1] = (I % 10) + 48;
S1 [2] = (code/10) + 48;
S1 [3] = (code % 10) + 48;
First = (* iter_begin). Num/10;
Second = (* iter_begin). Num % 10;
While (first! = 0)
{
Oldfirst = first;
Oldsecond = second;
Second = first % 10;
First = first/10; // The error is found here, and their order is not noticed. If it is first = first/10, then second = first % 10;
// The remainder of the new first is obtained, and the remainder of the oldfirst is required. You can write it like this.
// First = oldfirst/10; second = oldfirst % 10; do not care about their order
}
S1 [4] = oldfirst + 48;
S1 [5] = oldsecond + 48;
S1 [6] = (j/10) + 48;
S1 [7] = (j % 10) + 48;
S1 [8] = '/0 ';
Strcpy (* iter_begin). textID, s1 );
} // The End Of The for Loop
} // The external for loop ends.

For (int k = 1; k <= a4; ++ k, ++ (iter_begin) // process test rooms that are not full
{
Char s1 [9];
Int first = 0, second = 0, oldfirst = 0, oldsecond = 0; // used to find the first two digits of the student ID
S1 [0] = (I/10) + 48;
S1 [1] = (I % 10) + 48;
S1 [2] = (CODE/10) + 48;
S1 [3] = (CODE % 10) + 48;
First = (* iter_begin). num/10;
Second = (* iter_begin). num % 10;
While (first! = 0)
{
Oldfirst = first;
Oldsecond = second;
Second = first % 10;
First = first/10;
}
S1 [4] = oldfirst + 48;
S1 [5] = oldsecond + 48;
S1 [6] = (k/10) + 48;
S1 [7] = (k % 10) + 48;
S1 [8] = '/0 ';
Strcpy (* iter_begin). textid, S1 );
}

 

} // If (A4! = 0) Processing ended

Else
{
For (INT I = 1; I <= A3; ++ I) // you can specify a full classroom.
{
For (int j = 1; j <= a2; ++ j, ++ (iter_begin ))
{
Char s1 [9];
Int first = 0, second = 0, oldfirst = 0, oldsecond = 0; // used to find the first two digits of the student ID
S1 [0] = (I/10) + 48;
S1 [1] = (I % 10) + 48;
S1 [2] = (CODE/10) + 48;
S1 [3] = (CODE % 10) + 48;
First = (* iter_begin). num/10;
Second = (* iter_begin). num % 10;
While (first! = 0)
{
Oldfirst = first;
Oldsecond = second;
Second = first % 10;
First = first/10;
}
S1 [4] = oldfirst + 48;
S1 [5] = oldsecond + 48;
S1 [6] = (J/10) + 48;
S1 [7] = (J % 10) + 48;
S1 [8] = '/0 ';
Strcpy (* iter_begin). textid, S1 );
} // The End Of The For Loop
} // The external for loop ends.

} // Else ends

}

Void show_arrange_result ()
{
Char ch;
Iter_begin = SVEC. Begin ();
For (; iter_begin! = SVEC. End (); ++ iter_begin)
{
Cout <"name:" <setw (20) <(* iter_begin ). name <"student ID:" <setw (10) <(* iter_begin ). num <"Admission Ticket number" <setw (10) <(* iter_begin ). textID <endl;
}
Cin> ch;

}

Void main ()
{
Input_students_info ();
Produce_text_number ();
Show_arrange_result ();

}

/* Error summary:

(1) This is a low-level error and does not notice their order. If it is first = first/10, then second = first % 10;
The remainder of the new first is obtained, and the remainder of the oldfirst is required. You can write it like this.
First = oldfirst/10; second = oldfirst % 10; so do not care about their order

*/