Bash Shell parsing path Get file name and folder name

Preface or Today write a self-starter packaging script. Used to get the last file name from the path name. Here is a record of the implementation process.

Of course, in the end I will also give the official approach. (PS: Very embarrassing, realized that the original bash Shell has a ready-made function)
Gets the file name if the given path name is:

/tmp/csdn/zhengyi/test/zhengyi.txt

The awk solution uses a "/" delimiter, and then prints out the last part.

Implementation code such as the following:

Resfile= ' Echo/tmp/csdn/zhengyi/test/adb.log | Awk-f "/" ' {Print $NF} '

The official solution (basename) Bash shell itself provides the basename command, which is able to get the name of the last file of the pathname directly, implementing the code such as the following:

Resfile= ' Basename/tmp/csdn/zhengyi/test/adb.log '

Get folder name official solution (dirname) The Bash shell itself provides the dirname command, which is particularly handy to get the path to the corresponding folder name, implementing code such as the following:

Dirpath= ' Dirname/tmp/csdn/zhengyi/test/adb.log '

The awk solution has the flexibility to use separators, which are mixed with the normal form:

Dirpath= ' Echo/tmp/csdn/zhengyi/test/adb.log | Awk-f '/[^/]*$ ' {print '} '

Awk+for Loop Method:

Echo/tmp/csdn/zhengyi/test/adb.log | awk ' begin{res= '; fs= "/";} {for (i=2;i<=nf-1;i++) res= (res "/" $i);} End{print Res} '

Bash Shell parsing path Get file name and folder name