Binary to Text (ASCII) Conversion

Binary to Text (ASCII) Conversiondescription:

Write a function that takes in a binary string and returns the equivalent decoded text (the text is ASCII encoded).

Each of the 8 bits on the binary string represent 1 character on the ASCII table.

Note:in the case of a empty binary string your function should return an empty string.

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq; Public Static classkata{ Public Static stringBinaryToString (stringbinary) {      intCount = binary. Length/8; stringTMP =string.            Empty; List<Char> list =Newlist<Char>();  for(inti =0; I < count; i++) {tmp= Binary. Substring (i *8,8); List. ADD (Char) (Convert.ToInt32 (TMP,2))); }            return string. Join (string.  Empty,list); }}

Other people's Solution:

Binary. Split (8) uses the This keyword to extend the string class, adding extension methods split (int n)
The use of ienumerable<string> and yield

The use of Convert.tochar

usingSystem;usingSystem.Linq;usingSystem.Collections.Generic; Public Static classkata{ Public Static stringBinaryToString (stringbinary) {      return string. Join ("", Binary. Split (8). Select (s = Convert.tochar (Convert.ToInt32 (s),2)))); }    Staticienumerable<string> Split ( This stringSintsize) {     for(inti =0; i < s.length; i + =size) {      yield returnS.substring (i, math.min (size, s.length-i)); }  }}

Encoding.getstring method (byte[])

ASCIIEncoding

usingSystem;usingSystem.Text;usingSystem.Collections.Generic; Public Static classkata{ Public Static stringBinaryToString (stringbinary) {List<Byte> bytelist =NewList<byte>();  for(inti =0; I < binary. Length; i + =8) Bytelist.add (convert.tobyte (binary). Substring (i,8),2)); returnEncoding.ASCII.GetString (Bytelist.toarray ()); }}

The above version of the installation of the forced wording

usingSystem;usingSystem.Text;usingSystem.Linq; Public Static classkata{ Public Static stringBinaryToString (stringbinary) {      returnEncoding.ASCII.GetString (Enumerable.range (0, Binary. Length/8)             . Select (i= = Binary. Substring (i *8,8))             . Select (S= Convert.tobyte (S,2)).  ToArray ()); }}

Binary to Text (ASCII) Conversion