Binary Tree Right Side View

Source: Internet
Author: User

Description:

Given A binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can SE E ordered from top to bottom.

For example:
Given The following binary tree,

   1            <---/   2     3         <---\       5     4       <---

You should return [1, 3, 4] .

Code:

1vector<int> Rightsideview (TreeNode *root) {2Deque<treenode*>A;3Deque<treenode*>b;4vector<int>result;5         6         if(root==NULL)7             returnresult;8             9 A.push_back (root);Ten          while(!a.empty () | | |b.empty ()) One         { A             if( !a.empty ()) -             { -                 //go to the team first element theResult.push_back (A.front ()val); -                 //keep children of all elements of a in B and empty a -                  while(!a.empty ()) -                 { +treenode* p =A.front (); -                     if(p->Right ) +B.push_back (p->Right ); A                     if(p->Left ) atB.push_back (p->Left ); - A.pop_front (); -                 } -             } -             Else -             { inResult.push_back (B.front ()val); -                 //keep children of all elements of a in B and empty a to                  while(!b.empty ()) +                 { -treenode* p =B.front (); the                     if(p->Right ) *A.push_back (p->Right ); $                     if(p->Left )Panax NotoginsengA.push_back (p->Left ); - B.pop_front (); the                 } +             } A         } the          returnresult; +}
View Code

Binary Tree Right Side View

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