1024x768: [SCOI2009] Happy Birthday
Time Limit:20 Sec
Memory limit:256 MB
Topic Connection
http://www.lydsy.com/JudgeOnline/problem.php?id=1024
Description
Windy's birthday, in order to celebrate his birthday, his friends helped him to buy a side length of X and Y, respectively, a rectangular cake. Now including windy, there are a total of N people to divide the big cake, asking everyone to get the same area of cake. Windy Solo, everything can only be parallel to one side of the cake (either side), and must be cut into two pieces of this piece of cake. In this way, to cut into n pieces of cake, windy must cut N-1 times. To make every piece of cake look beautiful, we require that the maximum value of the long and short sides of the N-piece cake be the smallest. Can you help windy to find out the ratio?
Input
Contains three integers, X Y N
Output
Contains a floating-point number that retains 6 decimal places.
Sample Input
5 5 5
Sample Output
1.800000
HINT
100% data, meet 1 <= x, y <= 10000; 1 <= N <= 10
Test instructions
The following:
Data range n<=10, probably not a pressure or a search.
Our direct DFS (X,Y,N) indicates that the rectangle is now x, Y, and W, and the remaining n knives are not cut.
There is a greedy, I must want to cut down even more evenly
So it would be nice to just go with DFS.
Code:
#include <cstdio>#include<cmath>#include<cstring>#include<ctime>#include<iostream>#include<algorithm>#include<Set>#include<vector>#include<sstream>#include<queue>#include<typeinfo>#include<fstream>#include<map>#include<stack>typedefLong Longll;using namespacestd;//freopen ("d.in", "R", stdin);//freopen ("D.out", "w", stdout);#defineSspeed ios_base::sync_with_stdio (0); Cin.tie (0)#defineMAXN 1000100#defineMoD 10007#defineEPS 1e-9intNum;//const int INF=0X7FFFFFFF; //нчоч╢сConst intinf=0x3f3f3f3f; inline ll read () {ll x=0, f=1;CharCh=GetChar (); while(ch<'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} while(ch>='0'&&ch<='9') {x=x*Ten+ch-'0'; ch=GetChar ();} returnx*F;}//**************************************************************************************DoubleDfsDoubleXDoubleYDoublek) { if(k==1) { returnMax (x, y)/min (x, y); } Doubleans=inf; for(intI=1; i<k;i++) { DoubleAns1=max (Dfs (x/k*i,y,i), DFS (x/k* (k-i), y,k-i)); DoubleAns2=max (Dfs (x,y/k*i,i), DFS (x,y/k* (k-i), K-i)); Ans=min (ans,min (ans1,ans2)); } returnans;}intMain () {intX,y,n; scanf ("%d%d%d",&x,&y,&N); printf ("%.6lf\n", DFS (x*1.0, y*1.0N1.0));}
Bzoj 1024x768: [SCOI2009] Happy Birthday DFS