C # Implementation, C + + to convert Arabic amount to Chinese capital amount

--------Number Conversion Capital function---------//
A function to convert a digital amount into a Chinese capital number
function Changenummoneytochinese (Money)
{
var cnnums = new Array ("0", "one", "II", "three", "premises", "WU", "Lu", "Qi", "ba", "JIU"); Number of Chinese characters
var cnintradice = new Array ("", "Pick", "Bai", "thousand"); Unit
var cnintunits = new Array ("", "Million", "billion", "Mega"); Corresponding integer part expansion unit
var cndecunits = new Array ("Angle", "min", "mm", "CL"); Corresponds to fractional part units
var Cninteger = "whole"; Character followed by integer amount
var cnintlast = "Yuan"; Units after completion of the integer type
var maxnum = 999999999999999.9999; Maximum number of processed
var integernum; Amount of the whole number of parts
var decimalnum; Amount of small part
var chinesestr = ""; Chinese amount string for output
var parts; Array used after separating amount, pre-defined
if (Money = = "") {
Return "";
}
Money = parsefloat (money);
if (Money >= maxnum) {
Alert (' exceeds maximum processing number ');
Return "";
}
if (Money = = 0) {
Chinesestr = Cnnums[0] + cnintlast + cninteger;
return chinesestr;
}
Money = money.tostring (); Convert to String
if (Money.indexof (".") = = =-1) {
Integernum = money;
Decimalnum = ";
} else {
Parts = Money.split (".");
Integernum = Parts[0];
Decimalnum = Parts[1].substr (0, 4);
}
if (parseint (Integernum) > 0) {//Get integral type partial conversion
var zerocount = 0;
var intlen = integernum.length;
for (var i = 0; i < Intlen; i++) {
var n = integernum.substr (i, 1);
var p = intlen-i-1;
var q = P/4;
var m = p% 4;
if (n = = "0") {
zerocount++;
} else {
if (Zerocount > 0) {
Chinesestr + = Cnnums[0];
}
Zerocount = 0; Return to zero
Chinesestr + = Cnnums[parseint (n)] + cnintradice[m];
}
if (m = = 0 && Zerocount < 4) {
Chinesestr + = Cnintunits[q];
}
}
Chinesestr + = Cnintlast;
Integral part processing complete
}
if (decimalnum! = ") {//Decimal part
var declen = decimalnum.length;
for (var i = 0; i < Declen; i++) {
var n = decimalnum.substr (i, 1);
if (n! = ' 0 ') {
Chinesestr + = Cnnums[number (n)] + cndecunits[i];
}
}
}
if (chinesestr = = ") {
Chinesestr + = Cnnums[0] + cnintlast + cninteger;
} else if (Decimalnum = = ") {
Chinesestr + = Cninteger;
}
return chinesestr;
}

//----------------------------------------------------------------//

------------------------C + + implementation------------------------------//
//----------------------------------------------------------------//

#include <iostream>
#include <string>
#include <stdlib.h>
using namespace Std;

String Convertmoneycaps (long double moneysum)
{
long int temp_i = (long int) moneysum; /**//* Integer Part */
float temp_f = moneysum-temp_i; /**//* small number of parts */
int digit = 0, I, J, K, Num_i;
String Money ("");
Char num[20], *p;
Char name[][3] = {"Yuan", "Pick Up", "Bai", "Thousand", "million", "billion"};
Char numchar[][3] = {"0", "one", "II", "three", "premises", "WU", "Lu", "Qi", "ba", "JIU"};
Ltoa (temp_i, NUM, 10); /**//* integer part converted to string after processing */
p = num;
digit = strlen (num); /**//* integer partial number of bits */
/**//*--------Processing Integer part start--------*/
for (i = 1; i <= digit; i + +)
{
K = (digit-i)% 4;
if (IsDigit (*p))
{
Num_i = *p & 0xF; /* Convert characters to numbers such as ' 0 '-0, ' 1 '-1*/
/**//*--------Convert numbers start---------*/
if (num_i)
{
Money = money+ Numchar[num_i];
}
Else
{
if (k && (* (p + 1) &0xf))
Money + = "0";
}
/**//*--------Convert Digital end-------*/
/**//*---------Add count unit start----*/
if (k)
{
if (num_i)
Money = money + name[k];
}
Else
{
j = digit-i;
if (j)
Money = money + NAME[J/4 + 3];
Else
Money + = "Yuan";
}
/**//*--------Add count unit end--------*/
p++;
}
Else
{
Money = "encountered non-digital exit!";
return money;
}
}
/**//*--------Processing Integer part End--------*/
/**//*--------Processing of the decimal point start--------*/
if (Temp_f > 0.01)
{
if ((int) (TEMP_F*10)) money = money + numchar[(int) (TEMP_F*10)] + "Corner";
if ((int) (TEMP_F*100)%10) money = money + numchar[(int) (TEMP_F*100)%10] + "min";
}
/**//*--------Processing of decimal End--------*/
Money + = "whole";

return money;
}
int main ()
{
A long double x = 33.20;
cout << "Please input the money:";
CIN >> X;
cout << "Convert money Caps:";
String money = Convertmoneycaps (x);
cout << Money <<endl;
return 0;
}

C # Implementation, C + + to convert Arabic amount to Chinese capital amount