Calculate the IMEI checkpoint and the IMEI checkpoint

Calculate the IMEI checkpoint and the IMEI checkpoint

Calculate the IMEI checkpoint

The International Mobile device Identification Number (IMEI: International Mobile Equipment Identification Number) is a unique identifier of a Mobile device. It is attached to the logo on the back of the Mobile phone and stored in the Mobile device, it can be used to monitor stolen or invalid mobile devices. It is also the "file" and "ID card number" of the mobile phone in the manufacturer ". IMEI codes are centrally allocated by the GSM (Global Mobile Communications Association) and authorized to be reviewed by BABT (UK communications Certification Board. the total length is 15 digits, and each digit only uses 0 ~ 9 ).

IMEI consists of 15 digits, which are:

• 1. The first six digits (TAC, Type ApprovalCode) are "model approval numbers", which generally represent models.
• 2. The next two digits (FAC, Final Assembly Code) are "last Assembly numbers", which generally represent the origin.
• 3. the next 6 digits (SNR) are "serial numbers", which generally represent the production sequence numbers.
• 4. the last 1-digit (SP) is usually "0", which is the Verification Code and is used as an alternative.

IMEI verification code algorithm:

• (1) multiply the number of even digits by 2 to calculate the sum of single digits and ten digits respectively.
• (2) Add the odd digit number and the value calculated in the previous step.
• (3). If the number of digits obtained is 0, the check bit is 0. Otherwise, the value is 10 minus the single digit.

For example: 35 89 01 80 69 72 41 even digits multiply by 2 get 5*2 = 10 9*2 = 18 1*2 = 02 0*2 = 00 9*2 = 18 2*2 = 04 1*2 = 02, calculate the sum of odd digits and even digits. 3 + (1 + 0) + 8 + (1 + 8) + 0 + (0 + 2) + 8 + (0 + 0) + 6 + (1 + 8) + 7 + (0 + 4) + 4 + (0 + 2) = 63 => check bits 10-3 = 7

Char GetIMEICheckDigit (char * pp_Imei) {int I; int vl_Sum1 = 0, vl_Sum2 = 0, vl_Total = 0; int vl_Temp = 0; for (I = 0; I <14; I ++) {/* (1) Add odd digits (count from 1) */if (I % 2) = 0) {vl_Sum1 = vl_Sum1 + pp_Imei [I]-'0';} else {/* (2) Multiply the even number by 2, respectively, calculate the sum of single digits and ten digits (counting from 1) */vl_Temp = (pp_Imei [I]-'0') * 2; if (vl_Temp <10) {vl_Sum2 = vl_Sum2 + vl_Temp;} else {vl_Sum2 = vl_Sum2 + 1 + vl_Temp-10 ;}}/ * (1) + (2) */vl_Total = vl_Sum1 + vl_Sum2; /* if the number of digits obtained is 0, the check bit is 0. Otherwise, the value is 10 minus the single digit */if (vl_Total % 10) = 0) {return '0 ';} else {return (char) (10-(vl_Total % 10) + '0 ');}}

How can I calculate the IMEI verification code?

IMEI verification code algorithm:
(1) multiply the number of even digits by 2 to calculate the sum of single digits and ten digits respectively.
(2) Add the odd digit number and the value calculated in the previous step.
(3). If the number of digits obtained is 0, the check bit is 0. Otherwise, the value is 10 minus the single digit.
For example: 35 89 01 80 69 72 41 even digits multiply by 2 get 5*2 = 10 9*2 = 18 1*2 = 02 0*2 = 00 9*2 = 18 2*2 = 04 1*2 = 02, calculate the sum of odd digits and even digits. 3 + (1 + 0) + 8 + (1 + 8) + 0 + (0 + 2) + 8 + (0 + 0) + 6 + (1 + 8) + 7 + (0 + 4) + 4 + (0 + 2) = 63 => check bits 10-3 = 7
 
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