Calculates the number of occurrences of 9 in all integers 1 through 1000

Source: Internet
Author: User

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All integers, as long as the number of the 10 result is 9, that is, 9 appears once, each time count++ can be obtained 9 appears all the Times.

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The C language code is as follows:

# include <stdio.h>int main () {int i,x,count=0;          for (I=1; i<=1000; i++) {x = i%10;          if (x = = 9) {count++;      }} printf ("One to 100 of 9 occurrences:%d\n", count); return 0;}

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Dry Tip: about # define: In the C language of the Convention, #define语句中的标识符都是大写.

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This article is from the "Nobody" blog, please be sure to keep this source http://814193594.blog.51cto.com/10729329/1700846

Calculates the number of occurrences of 9 in all integers 1 through 1000

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