1. The essence of the capacitive buck: the discharge of the capacitance, charge and discharge current determines its ability to provide the load current. Generally used in low-cost, small-current scenarios. Load current is available at dozens of Mah. Note that this circuit is unsafe and the 12v voltage is mounted on a 220V voltage. This circuit is half-wave rectified.
2. When the 220v increases from zero, at this time the largest current, increase to 220v when the current is the smallest, and then 220v began to reduce the C2 power discharge, the current began to increase negative, when 220v reduced to 0 o'clock, the capacitance current negative to increase to the maximum. When the 220v is increased by 0 negative, the capacitance current is reduced by the negative direction. When the 220v negative is increased to maximum, the capacitance current is reduced from negative to 0. The 220v then decreases from negative to positive, and the capacitance current starts to increase from 0. The waveform diagram can be viewed more visually.
3. Tolerance Zc = 1/(2*3.14*f*c), Iac = 220v/zc,ic = 0.44*iac, obtained from: Ic = 30000C. That is, the 1uf capacitance provides 30mA of current.