Chapter 1 answers to all exercises in Chapter 13th of Wang Shuang's Assembly Language

Source: Internet
Author: User

Note that there are programs and test programs. For example, exp1303.asm refers to Chapter 13's third question. exp1303. ASM refers to the test of exp1303 program...

 

; Exp1301.asm

 

Install the 7ch Interrupt Routine
Function: calculates the square of a word number.
;
;
Assume Cs: Code

Code segment
Start:
; Copy the code to a non-system management area
MoV ax, CS
MoV ds, ax
MoV Si, offset sqr; copy from sqr of CS segment to 0: 200

MoV ax, 0
MoV es, ax
MoV Di, 200 h

MoV CX, offset sqrend-offset sqr; CX is the number of Code bytes to be copied
ClD
Rep movsb; call movsb to copy ES: [di] bytes to DS: [Si]

; Set the interrupt vector
MoV ax, 0
MoV es, ax
MoV word ptr es: [7ch * 4], 200 h; Use Word PTR to indicate that a word is to be copied
MoV word ptr es: [7ch * 4 + 2], 0

MoV ax, 3
Int 7ch

MoV ax, 4c00h
Int 21 h

Sqr:
Mul ax
Iret
Sqrend:
NOP

Code ends

End start

 

 

; Exp1302.asm

 

 

Install the 7ch Interrupt Routine
Function: Display strings starting with DS: [Si ].

Assume Cs: Code

Data Segment
DB "Welcome to MASM! ", 0
Data ends

Code segment
Start:
; Copy the code to a non-system management area
MoV ax, CS
MoV ds, ax
MoV Si, offset int7c; copy from int7c of CS segment to 0: 200

MoV ax, 0
MoV es, ax
MoV Di, 200 h

MoV CX, offset int7cend-offset int7c
ClD
Rep movsb

; Set the interrupt vector
MoV ax, 0
MoV es, ax
MoV word ptr es: [7ch * 4], 200 h
MoV word ptr es: [7ch * 4 + 2], 0

; DH = number of rows, DL = strong, CL = color, DS: Si points to the first address
MoV DH, 10
MoV DL, 10
MoV Cl, 2

MoV ax, Data
MoV ds, ax

MoV Si, 0
Int 7ch

MoV ah, 01 H
Int 21 h

MoV ax, 4c00h
Int 21 h

Int7c:
PUSH AX
Push BX
Push CX
Push DX
Push es

The address y = 160 * (number of rows-1) + number of columns * 2-2, b800: Y
; Cyclically write the strings in the parameters into the memory of the video card, and return the results if 0 is detected.

; BX = 160 * (number of rows-1)
Sub DH, 1 h
MoV Al 160
Mul DH
MoV BX, ax; BX is the offset value calculated based on the number of rows

; AX = number of columns * 2-2
MoV Al, 2
Mul DL
Sub ax, 2; offset value calculated based on the number of Columns
Add Bx, ax; The sum of the number of rows and columns exists in BX.

MoV ax, 0b800h
MoV es, ax

MoV DL, Cl; Save the font color attribute
MoV CH, 0

S_show_str:
MoV Cl, DS: [Si]
MoV ES: [BX], Cl
Jcxz OK _show_str

MoV ES: [bx + 1], DL

INC Si
Add Bx, 2
JMP short s_show_str

OK _show_str:
Pop es
Pop DX
Pop CX
Pop BX
Pop ax
Iret
Int7cend:
NOP

Code ends

End start

 

; Exp1302t. ASM

; Test procedure of the previous program

 

; Test 7ch interrupt, display string

Assume Cs: Code

Data Segment
DB "Welcome to MASM 6.11! ", 0
Data ends

Code segment
Start:
MoV ax, Data
MoV ds, ax

MoV DH, 10
MoV DL, 10
MoV Cl, 2
MoV Si, 0

Int 7ch

MoV ax, 4c00h
Int 21 h
Code ends

End start

 

; Exp1303.asm

 

Install the 7ch Interrupt Routine
Function: converts all strings starting with DS: Si and ending with 0 to uppercase.

Assume Cs: Code

Data Segment
DB "Welcome to MASM! ", 0
Data ends

Code segment
Start:
; Copy the code to a non-system management area
MoV ax, CS
MoV ds, ax
MoV Si, offset int7c; copy the interrupt code from int7c of CS segment

MoV ax, 0
MoV es, ax
MoV Di, 200 h

MoV CX, offset int7cend-offset int7c
ClD
Rep movsb

; Set the interrupt vector
MoV ax, 0
MoV es, ax
MoV word ptr es: [7ch * 4], 200 h
MoV word ptr es: [7ch * 4 + 2], 0

MoV ax, Data
MoV ds, ax
MoV Si, 0
Int 7ch

MoV ah, 01 H
Int 21 h

MoV ax, 4c00h
Int 21 h

Int7c:
 
; Compares the characters starting with DS: [Si]. If it is a lowercase letter, converts it to uppercase.
Because it ends with 0, jcxz can be used here
The lower-case letters are in the range of 61h ~ 7ah, 20 h less capital letters than it
And can be judged by JB 61 H and Ja 7ah, and cyclically
Push CX
Push Si
 
MoV CH, 0
Loop1:
MoV Cl, DS: [Si]
Jcxz loop1end
 
CMP Cl, 61 H
JB notcase
CMP Cl, 7ah
Ja notcase

Sub Cl, 20 h
MoV DS: [Si], Cl
INC Si
JMP short loop1

Notcase:
INC Si
JMP short loop1

Loop1end:
Pop Si
Pop CX
Iret

Int7cend:
NOP

Code ends

End start

 

; Exp1303t. ASM

Test exp1303. Use the 7ch interrupt to convert all lowercase letters of DS: [Si] To uppercase letters.
; Show_str is shown below

Note: Using and bytr PTR [Si] And 110111b to uppercase can simplify the process.

Assume Cs: Code

Data Segment
DB "Welcome to MASM! ", 0
Data ends

Stack segment

Stack ends

Code segment
Start:
 
MoV ax, Data
MoV ds, ax
MoV Si, 0
 
Int 7ch

MoV ax, Data
MoV ds, ax
MoV Si, 0
MoV DH, 2
MoV DL, 3
MoV Cl, 2
Call show_str

MoV ah, 01 H
Int 21 h

MoV ax, 4c00h
Int 21 h
 

; Name: show_str
Function: Specify the position and color to display a string ending with 0
; Parameter: (DH) = row number (0--24), (DL) = column number (0--79)
; (CL) = color, DS: Si points to the first address of the string
; Return: None
Show_str:
PUSH AX
Push BX
Push CX
Push DX
Push es

The address y = 160 * (number of rows-1) + number of columns * 2-2, b800: Y
; Cyclically write the strings in the parameters into the memory of the video card, and return the results if 0 is detected.

; BX = 160 * (number of rows-1)
Sub DH, 1 h
MoV Al 160
Mul DH
MoV BX, ax; BX is the offset value calculated based on the number of rows

; AX = number of columns * 2-2
MoV Al, 2
Mul DL
Sub ax, 2; offset value calculated based on the number of Columns
Add Bx, ax; The sum of the number of rows and columns exists in BX.

MoV ax, 0b800h
MoV es, ax

MoV DL, Cl; Save the font color attribute
MoV CH, 0

S_show_str:
MoV Cl, DS: [Si]
MoV ES: [BX], Cl
Jcxz OK _show_str

MoV ES: [bx + 1], DL

INC Si
Add Bx, 2
JMP short s_show_str

OK _show_str:
Pop es
Pop DX
Pop CX
Pop BX
Pop ax

RET

Code ends

End start

 

; Exp1304.asm

 

; Use BIOS interrupt and DOS interrupt

Assume Cs: code, DS: Data

Data Segment
DB 'Welcome to ASM! ',' $'
Data ends

Stack segment

Stack ends

Code segment
Start:
; Call BIOS Interrupt Routine
MoV ah, 2
MoV BH, 0
MoV DH, 5
MoV DL, 12
Int 10 h

MoV ah, 9
MoV Al, 'A'
MoV BL, 11001010b
MoV BH, 0
MoV CX, 3
Int 10 h

; Call dos Interrupt Routine
MoV ax, 4c00h
Int 21 h

Code ends

End start

 

; Exp1305.asm

 

Assume Cs: code, DS: Data

Data Segment
DB 'Welcome to ASM! ',' $'
Data ends

Stack segment

Stack ends

Code segment
Start:
MoV ah, 2; BIOS light indicator routine
MoV BH, 0; Page 0th
MoV DH, 5; DH row number
MoV DL, 12; dl column number
Int 10 h

MoV ax, data;
MoV ds, ax
MoV dx, 0; DS: DX points to the first address of the string data: 0
MoV ah, 9; Child Program of Interrupt Routine No. 21
Int 21 h

MoV ax, 4c00h
Int 21 h

Code ends

End start

 

; Exp1306.asm

 

; Use int 7ch instead of loop function, BX is the offset address, CX is the number of cycles
; 7ch installation interrupted
The key is to convert the Cs: IP address to be jumped to by the current program after int7ch.

When the call is interrupted, several important registers will press the stack. The sequence is: Mark register, Cs, IP
The principle here is to change the IP value in the stack to the starting address of the loop when calling the interrupt 7 CH, and then return the interrupt
; Understand the above two points, this question is OK, otherwise the access will go wrong, encountering the operating system's restricted area

Assume Cs: Code

Code segment
Start:
; Copy the code to the 0: 200 memory Zone
MoV ax, CS
MoV ds, ax
MoV Si, offset int7c

MoV ax, 0
MoV es, ax
MoV Di, 200 h
 
MoV CX, offset int7cend-offset int7c
ClD
Rep movsb

; Installation interrupt variable
MoV ax, 0
MoV es, ax
MoV word ptr es: [7ch * 4], 200 h
MoV word ptr es: [7ch * 4 + 2], 0

MoV ax, 4c00h
Int 21 h

Int7c:
Push BP

MoV bp, SP
Dec CX
Jcxz offset int7cok

Sub [bp + 2], BX; IP

Int7cok:
Pop BP
Iret
Int7cend:
NOP

Code ends

End start

 

; Exp1306t

 

; Use int 7ch instead of loop function, BX is the offset address, CX is the number of cycles
; Display 80' in the middle of the screen '! '

Assume Cs: Code

Code segment
Start:
MoV ax, 0b800h
MoV es, ax
MoV Di, 160*12; 12 rows, right in the middle of the 80*24 Screen

MoV BX, offset se-offset s
MoV CX, 80
S:
MoV byte ptr es: [di], '! '
MoV byte ptr es: [di + 1], 2
Add Di, 2
Int 7ch
SE:
NOP

MoV ax, 4c00h
Int 21 h

Code ends

End start

 

; Exp1307.asm

 

Directly address the table and call the bios, DOS interrupt display string

Assume Cs: Code

Code segment
S1 dB 'good, better, best! ',' $'
S2 dB 'Never let it rest! ',' $'
S3 dB 'till good is better ',' $'
S4 dB 'and better, best.', '$'
S DW offset S1, offset S2, offset S3, offset S4
Row dB

Start:
MoV ax, CS
MoV ds, ax
MoV BX, offset s
MoV Si, offset row
MoV CX, 4
OK:
BiOS cursor placement
MoV BH, 0
MoV DH, [Si]
MoV DL, 0
MoV ah, 2
Int 10 h

; Dos display string routine
MoV dx, [BX]
MoV ah, 9
Int 21 h

INC Si; row is dB, one byte
Add Bx, 2; Because DW occupies two bytes, add 2

Loop OK

MoV ax, 4c00h
Int 21 h
Code ends

End start

 

In this chapter, I have learned more about interrupt. Through debugging and observation, I can better understand the changes in the stack and various registers when I call the int and iret commands...

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