COdeforces # mongod Cunning Gena (pressure DP)
A boy named Gena really wants to get to the "Russian Code Cup" finals, or at least get a t-shirt. but the offered problems are too complex, so he made an arrangement with hisNFriends that they will solve the problems for him.
The maid are offeredMProblems on the contest. For each friend, Gena knows what problems he can solve. But Gena's friends won't agree to help Gena for nothing:I-Th friend asks GenaXIRubles for his help in solving all the problems he can. Also, the friend agreed to write a code for Gena only if Gena's computer is connected to at leastKIMonitors, each monitor costsBRubles.
Gena is careful with money, so he wants to spend as little money as possible to solve all the problems. help Gena, tell him how to spend the smallest possible amount of money. initially, there's no monitors connected to Gena's computer.
Input
The first line contains three integersN,MAndB(1? ≤?N? ≤? 100; 1? ≤?M? ≤? 20; 1? ≤?B? ≤? 109)-the number of Gena's friends, the number of problems and the cost of a single monitor.
The following 2NLines describe the friends. Lines number 2IAnd (2I? +? 1) contain the information aboutI-Th friend. The 2I-Th line contains three integersXI,KIAndMI(1? ≤?XI? ≤? 109; 1? ≤?KI? ≤? 109; 1? ≤?MI? ≤?M)-The desired amount of money, monitors and the number of problems the friend can solve. The (2I? +? 1)-th line containsMIDistinct positive integers-the numbers of problems thatI-Th friend can solve. The problems are numbered from 1M.
Output
Print the minimum amount of money Gena needs to spend to solve all the problems. Or print-1, if this cannot be achieved.
Sample test (s) input
2 2 1100 1 12100 2 11
Output
202
Input
3 2 5100 1 11100 1 12200 1 21 2
Output
205
Input
1 2 11 1 11
Output
-1
We found that because the number of required monitors is different, we need to sort the number of monitors from small to large, and then press DP, because the number of the following monitors exceeds the front, therefore, we do not have to consider whether the monitor is adequate. The following is the pressure DP.
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#includewww.bkjia.com
using namespace std;#define REPF( i , a , b ) for ( int i = a ; i <= b ; ++ i )#define REP( i , n ) for ( int i = 0 ; i < n ; ++ i )#define CLEAR( a , x ) memset ( a , x , sizeof a )typedef long long LL;typedef pair
pil;const LL INF=1e19;LL dp[1<<20];struct node{ int cost,k; int s;}e[110];int n,m,b,num;int cmp(node l1,node l2){ return l1.k