Crazy tea partygrade: 10/discount: 0.8 time limit: 1000 ms memory limit: 65536 K description
N participating ants of <crazy Tea Party> sit around the table. each minute one pair of neighbors can change their places. find the minimum time (in minutes) required for all maid to sit in reverse order (so that left neighbors wocould become right, and right-left ).
Input
The first line is the amount of tests. Each next line contains one integer N (1 <=n <= 32767)-the amount of crazy tea participant ipants.
Output
For each number n of participants to crazy Tea Party print on the standard output, on a separate line, the minimum time required for all participants to sit in reverse order.
Sample Input
3
4
5
6
Sample output
2
4
6
#include<iostream>using namespace std;int main(){ int T; int n; int temp; int a,b; cin>>T; while(T--) { cin>>n; if(n%2==0) { temp=(n/2-1)*n/2; } else { a=n/2; b=n-n/2; temp=((a-1)*a+(b-1)*b)/2; } cout<<temp<<endl; }return 0;}