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DB2 How to calculate the difference of two times how many months. such as 2015-10-10 and 2014-1-12

Source: Internet
Author: User
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SELECT
  Timestampdiff (Timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "Interval year",
  Timestampdiff (+, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "Interval quarter",
  Timestampdiff (+, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "Interval Month",
  Timestampdiff (+, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "Interval Week",
  Timestampdiff (+, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "Interval Day",
  Timestampdiff (8, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "at Interval",
  Timestampdiff (4, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "interval Division",
  Timestampdiff (2, char (timestamp (' 2013-12-30 20:30:30 ')-timestamp (' 2001-09-26 15:24:23 ')) as "interval seconds"
From SYSIBM. SYSDUMMY1;

DB2 How to calculate the difference of two time months. such as 2015-10-10 and 2014-1-12

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