# Don't pass me the ball.

Source: Internet
Author: User

Title Description Description

The CCC football match is a little different from the traditional football game, when a goal is scored in ascending order and only if the 4 players who have come into contact with the ball have the shirt number.

The player's shirt number is from 1 to 99, and each person's number is different.

Given the last scoring player's shirt number, please figure out how many legitimate combinations of players will be able to produce this goal.

Enter a description Input Description

Enter an integer 1<=j<=99 that represents the player's shirt number

Output description Output Description

The output has only one row and contains an integer that represents the number of combinations that make the player with the last goal numbered J.

Sample input Sample Input

Sample Input 1:4

Sample Input 2:2

Sample Input 3:90

Sample output Sample Output

Sample Output 1:1

Sample Output 2:0

Sample Output 3:113,564

Ideas:

This question test our permutation combination, but Ben Little did not learn this thing, but anyway, find the law everyone is will!

We can make a special judgment on this topic by the j<4, there is no answer

Since the requirement is four players, the first player's value range is 1~j-3, which means we can j-2,j-1,j the three players ignored, from the previous players to discuss.

F (4) =f (1+3) =1

F (5) =f (2+3) =2+1+1 = 2*1 + 1*2

F (6) =f (3+3) =3+2+1+2+1+1 = 3*1 + 2*2 + 1*3

F (7) =f (4+3) =4+3+2+1+3+2+1+2+1+1 = 4*1 + 3*2 + 2*3 + 1*4

So it's not hard to launch

F (i+3) =i*1+ (i-1) *2+ (i-2) *3+......+2* (i-1) +1*i

`/*Super-Simple code*/#include<iostream>using namespacestd;Long Longans;intN;intMain () {CIN>>N; if(n<4) {cout<<0;return 0;} intk=n-3;  for(intI=1, j=k;i<=k;i++,j--) ans+=i*J; cout<<ans;}`

Don't pass me the ball.

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