Enter several numbers and separate the series of examples with commas

Enter n numbers, separated by commas

The process is as follows:

char Str[100];char ch = ' str;while '; int i = 0;vector<int> v;int tmp = 0;cin >> str[i (WHI]! =            Le (str[i]!= ' && str[i]! = ', ') {TMP = TMP * + str[i]-' 0 '; ++i;} V.push_back (TMP); if (str[i] = = ' \ ") break;tmp = 0;++i;}

Thunder written test Programming 2 questions

#include  <iostream> #include  <vector>using namespace std;int main () {       int n=5;      vector<int> v;   char str[100];  cin >> str;  int i = 0;   int tmp = 0;  //////////////////////////////////////handles comma-separated numbers   while   (str[i] !=  ') {  while  (str[i] !=  '  && str[i]  !=  ', ') {  if  (str[i] ==  ' A ')   str[i] =  ' 1 ';   else if  (str[i] ==  ' J '  | |  str[i] ==  ' Q '  | |  str[i] ==  ' K ')   str[i] =  ' 0 '  + 10;  tmp =  tmp * 10 + str[i]-' 0 ';   ++i;  }  v.push_back (TMP);   if  (str[i] ==  ')   break;  tmp = 0;  ++i;  }  ////////////////////////   int a[3] = { 0 };  int  has = 0;  for  (int i = 0; i < 3; ++i) {   for  (int j = i+1; j < 4; ++j) {  for  (int  K = j+1; k < 5; ++k) {  if  ((v[i] + v[j] +  V[k]) >=10&& (V[i] + v[j] + v[k])  % 10 == 0) {  a[0]  = i;  a[1] = j;  a[2] = k;  ++has;   break;  }  }  }  }  if  (has == 0)    cout <<  "None"  << endl;  else{  int sum = 0 ;   for  (int i = 0; i < 5; ++i) {  if  (I != a[0]  && i != a[1] && i != a[2]) {  sum +=  v[i];  }  }  if  (sum >= 10 && sum  % 10 == 0) {  cout <<  "ten" &NBSP;&LT;&LT;&NBSP;ENDL;&NBSP;&NBSP;}   else{  cout << sum % 10 << endl;  }   }  system ("pause");       return 0;}

This article from "Zero Egg" blog, declined reprint!

Enter several numbers and separate the series of examples with commas