Case: compile a function to convert the input Chinese date to the Arabic digit date.
For example, from January 1, 2012 to January 21, to December 21. (Process "10"
Question: 1. * day 10; 2. day 13; 3. 23; 4. day 30 ;)
In section 4, the translation of "10" is different. 1 → 10; 2 → 1; 3 → No translation; 4 → 0 [the year part is not
The '10' may appear in the month and day sections .]
Test data: July 6, July 7
July 9, October 24, 2010, and October 20, 2010
Analysis: You can consider using dictionaries to give keys and output corresponding values.
The difficulty lies in dealing with ten
Case handling
A number of 10
The two numbers are in the first 1
The two numbers are in the last 0.
The three numbers are in the middle (certain) and are not translated.
Using system;
Using system. Collections. Generic;
Using system. LINQ;
Using system. text;
Using system. Threading. tasks;
Namespace Date Format Conversion
{
Class Program
{
Static void main (string [] ARGs)
{
While (true)
{
Console. writeline ("Enter the date ");
String dates = console. Readline (). Trim ();
Stringbuilder date = new stringbuilder ();
Date = getdateformat (dates); // the specific format conversion is encapsulated into a method
Console. writeline (date );
Console. readkey ();
Console. Clear ();
}
}
/// <Summary>
/// Method: dictionary, and then call format conversion
/// </Summary>
/// <Param name = "date"> </param>
/// <Returns> </returns>
Private Static stringbuilder getdateformat (string date)
{
// Declare the dictionary and store the key values related to the date
Dictionary <char, char> DIC = new dictionary <char, char> ();
// Give a string, put the keys and values that may appear, and perform 10 Special Operations
String TXT = "0 0 a 1 2 3 3 4 5 6 6 7 8 9 9 ";
// Split the TXT file to obtain the key values and store them in the dictionary.
String [] keyValue = TXT. Split (New char [] {''}, stringsplitoptions. removeemptyentries );
// Traverse the array and store the corresponding key-value pairs respectively
For (INT I = 0; I <keyValue. length; I ++)
{
If (! Dic. containskey (keyValue [I] [0])
{
Dic. Add (keyValue [I] [0], keyValue [I] [1]);
}
}
// Call the method to return the date in numeric format
Return getdigitdate (DIC, date );
}
/// <Summary>
/// Method: Format Conversion
/// </Summary>
/// <Param name = "dic"> </param>
/// <Param name = "date"> </param>
/// <Returns> </returns>
Private Static stringbuilder getdigitdate (Dictionary <char, char> DIC, string date)
{
// Convert string to character array
Char [] CHS = date. tochararray ();
Stringbuilder sb = new stringbuilder ();
For (INT I = 0; I <CHS. length; I ++)
{
Processing 10
Translation:
10
Dozens of items
Dozens of 0
Dozens of non-Translators
If (CHS [I] = '10 ')
{
X indicates the characters not included in the dictionary.
// 10x10x10
If (! Dic. containskey (CHS [I-1]) &! Dic. containskey (CHS [I + 1])
{
SB. append ("10 ");
}
// Dozens of X 1
Else if (! Dic. containskey (CHS [I-1]) & DIC. containskey (CHS [I + 1])
{
SB. append ("1 ");
}
// Dozens of X dozens of x 0
Else if (DIC. containskey (CHS [I-1]) &! Dic. containskey (CHS [I + 1])
{
SB. append ("0 ");
}
// Dozens of rows x null
Else if (! Dic. containskey (CHS [I-1]) &! Dic. containskey (CHS [I + 1])
{
SB. append ("");
}
}
Else if (DIC. containskey (CHS [I])
{
// Output the corresponding value if the dictionary exists.
SB. append (DIC [chs [I]. tostring ());
}
Else if (CHS [I] = 'Year' | CHS [I] = 'month ')
{
// Year and month-replaced
SB. append ("-");
}
}
Return Sb;
}
}
}
Conclusion: the difficulty of this question lies in the processing of ten. It can return 10, 1, 0, ""; four cases; the dictionary is of the <char, char> type, to judge each character of the input string, if you use CHS [I] = 'X'; then
Return new string (CHS); the string method will be tricky (for example, it is difficult to process it when it is translated into 10); at this time, you need to think of the stringbuilder method.
Enter the Chinese Date and output the date of the corresponding digit format
