Exercise 5.2 Summing data values

Exercise 5-2. Define an array, data, with elements of type double. Write a loop that
Would store the following sequence of values in corresponding elements of the array:

1/(2*3*4) 1/(4*5*6) 1/(6*7*8) ... up to 1/(200*201*202)

Write another loop that would calculate the following:

DATA[0]-data[1] + data[2]-data[3] + ...-data[99]

Multiply The result of this by 4.0, add 3.0, and output the final result. Do you recognize the
Value you get?

1 //Exercise 5.2 Summing data values2#include <stdio.h>3 4 intMainvoid)5 {6   Doubledata[ -];//Stores Data Values7   Doublesum =0.0;//Stores sum of terms8   DoubleSign =1.0;//sign-flips between +1.0 and-1.09size_t i =0;Ten  One   intj =0; A    for(i =0; I <sizeof(data)/sizeof(Double) ; ++i)//God horse means?  -   { -j =2* (i +1); theData[i] =1.0/(J * (J +1) * (j +2)); -Sum + = sign*Data[i]; -Sign =-Sign ; -  } +  -    //Output The result +printf"The result is%.4lf\n",4.0*sum +3.0); Aprintf"The result is a approximation of pi, isn ' t that interesting?\n"); at     return 0; -}

Exercise 5.2 Summing data values