Fast location to the middle of a single linked list of nodes __ data structure

Source: Internet
Author: User
#include <stdio.h>
#include <malloc.h>
typedef struct NODE
{
int data;
struct Node *next;
}node,*linkedlist;
/*
The following procedure establishes a single linked list for the tail difference method
*/
void Tailcreat (LinkedList &l,int i)
{
Int J;
LinkedList p1,p2;
L = (linkedlist) malloc (sizeof (Node));
P1=l;

for (j=1;j<=i;j++)
{
P2= (LinkedList) malloc (sizeof (Node));
p2->data=j;
p1->next=p2;
P1=P2;
}
p1->next=null;
}
/*
Delete a single linked list
*/
void Remove (LinkedList &l)
{
LinkedList p,q;//p is the node that is currently being deleted, if he is deleted. We also want to delete his next node. Because P is no longer here, so at this point,
We need to use Q to record the next node of P.
p=l->next;
while (p)
{
q=p->next;
Free (p);
p=q;
}
l->next=null;
}
/*
Quickly navigate to the middle node of a single linked list
Defines a quick pointer search and a slow pointer middle. Fast each step two steps, slow each time take one step. When the fast to the end of the time, slowly just go to the middle.
*/
int Middle (linkedlist l,int *e)
{
LinkedList Search,middle;
Search=middle=l;
while (Search->next!=null)
{
if (search->next->next!=null)
{
search=search->next->next;
middle=middle->next;
}
Else
{
search=search->next;
}
}
*e=middle->next->data;
return 1;
}
int main ()
{
int e;
LinkedList l,p;
Tailcreat (l,9);
printf ("%d\n", l->next->data);
p=l->next;

while (p!=null)//View all the elements in the list
{
printf ("%d", p->data);
p=p->next;
}
printf ("\ n");
Middle (l,&e);
printf ("%d\n", e);
Remove (L);
printf ("%d\n", l->next->data);//The program cannot run at this time because the L-next is empty,
return 1;
}

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