FCC Advanced Algorithm problem Register find change

Exact Change

Design a Cashier program checkCashRegister() that takes the purchase price ( price ) as the first parameter, the payment amount ( cash ) as the second parameter, and the cash register in the Change ( cid ) as the third parameter.

cidis a two-dimensional array with the current available change.

When there's not enough money in the register. 0 O'Clock returns a string. "Insufficient Funds" if it happens, the string is returned "Closed" .

Otherwise, the list of changes that should be retrieved is returned, and there are two-dimensional arrays from large to small.

Global Object

Code:

1 functionCheckcashregister (Price, cash, CID) {2         varobj = {};3         varnum = 0;4         varOdd = cash-Price ;5         vararr = [];6         varNEWARR = [];7         varA = 0;8 9          for(vari = 0; i < cid.length; i++) {Ten           //change the first and second entries of this two-dimensional array to the properties and property values of the new object. One             vars = cid[i][0]; AObj[s] = cid[i][1]; -           //Add up The sum of the register change -num + = cid[i][1]; the         } -         if(Odd = = =num) { -           //returns the string "Closed" if the money in the register is odd equal to the money that needs to be found -             return"Closed"; +         } -          for(varj = 0; J < Object.keys (obj). length; J + +) { +           //Traversing Object Properties A             varName = Object.keys (obj) [8-j]; at           //create a new array of dollar amounts -             varFigure = [100, 20, 10, 5, 1, 0.25, 0.1, 0.05, 0.01]; -            - fi1 (); -            -             if(A > 0) { inArr.push ([Name, Figure[j] *a]); -A = 0; to             } +         } -         functionFi1 () { the             if(Odd >= Figure[j] && Obj[name] >=Figure[j]) { *               //to judge a odd, if it is larger than a certain denomination and has a banknote of that denomination on the radio $Odd = odd-Figure[j];Panax Notoginseng               //js accuracy problem, 2=1.999999, so to use Math.Round () to round -Odd = Math.Round (odd * 10000)/10000; theObj[name] = Obj[name]-Figure[j]; +Obj[name] =Math.Round (Obj[name]); A               //this A is used to determine if there are multiple banknotes of uniform face value, which is added in the IF statement above to the empty array arr . theA + = 1; + fi1 (); -             } $         } $         if(Odd = = 0) { -           //If you can change and have the rest, return a list of changes that should be recovered -             returnarr; the}Else if(Odd > 0) { -           //returns the string "Insufficient Funds" if the money in the radio is not enough to find zeroWuyi             return"Insufficient Funds"; the         } -     } Wu  -Checkcashregister (19.50, 20.00, [ About["PENNY", 0.50], $["Nickel", 0], -["DIME", 0], -["QUARTER", 0], -["One", 0], A["FIVE", 0], +["TEN", 0], the["Twenty", 0], -["One Hundred", 0] $]);

FCC Advanced Algorithm problem Register find change