Find the value of the matrix _ for multiple table substitution password decryption do prepare __ modern cryptography

Introduced:

First enter n, then enter n * n matrix, and finally output the value of the matrix.

#include <bits/stdc++.h> using namespace std;
float result;
int a[1010][1010];
float aa[1010][1010];
int n;
        void Swap (float *a, float *b) {for (int i = 1; I <= n; ++i) {Float temp = a[i];
        A[i] = B[i];
    B[i] = temp;
    } void GetValue () {float mul;
    int iter = 0;
    result = 1.0;
            for (int i = 1; I <= n; ++i) {if (aa[i][i] = 0) {for (int k = i + 1; k <= N; ++k)
                    {if (Aa[k][i]!= 0) {Swap (Aa[i], aa[k]);
                    iter++;
                Break 
                for (int k = i + 1; k <= N; ++k) {if (Aa[k][i]!= 0) {
                Mul =-1 * (Aa[k][i]/aa[i][i]);
                Aa[k][i] = 0;
                for (int p = i + 1; p <= N; ++p) {aa[k][p] + = Mul * Aa[i][p];
    }
            }
        }for (int i = 1; I <= n; ++i) result *= Aa[i][i];
if (iter% 2 = 1) result =-result;
    } void Input () {scanf ("%d", &n);
            for (int i = 1; I <= n; ++i) for (int j = 1; j <= N; ++j) {scanf ("%d", &a[i][j]);
        AA[I][J] = A[i][j]; } void Putout () {for (int i = 1; I <= N. ++i) {for (int j = 1; j <= N; ++j) cout <& Lt
        AA[I][J] << "";
    cout << Endl;
    int main () {Input ();
    GetValue ();
    Putout ();
cout << result << Endl;
 }