4540: [Hnoi2016] Sequence

Source: Internet
Author: User

4540: [Hnoi2016] Sequence

https://www.lydsy.com/JudgeOnline/problem.php?id=4540

Analysis:

MO team +rmq+ monotonous stack.

Consider adding a point after the interval has changed. [L,r]->[l,r+1], increased the r-l+1 segment. Set [l,r+1] the minimum value in P, then the left end of the l~p-1 interval, the answer is a[p], p right Also

Code:

1#include <cstdio>2#include <algorithm>3#include <cstring>4#include <cmath>5#include <iostream>6#include <cctype>7#include <Set>8#include <vector>9#include <queue>Ten#include <map> One #defineFi (s) freopen (S, "R", stdin); A #defineFo (s) freopen (S, "w", stdout); - using namespacestd; -typedefLong LongLL; the  -InlineintRead () { -     intx=0, f=1;CharCh=getchar (); for(;! IsDigit (CH); Ch=getchar ())if(ch=='-') f=-1; -      for(; isdigit (ch); Ch=getchar ()) x=x*Ten+ch-'0';returnx*F; + } -  + Const intN =100005; A  at intA[n], Sk[n], bel[n], l[n], r[n], f[n][ -], log[n]; - LL Ans[n], sl[n], sr[n], Answer; - structque{ -     intL, R, id; -     BOOL operator< (ConstQue &a)Const { -         returnBel[l] = = Bel[a.l]? R < A.r:bel[l] <BEL[A.L]; in     } - }q[n]; to  +InlineintMin (intIintj) { -     returnA[i] < A[j]?i:j; the } *InlineintCalc (intLintr) { $     if(R <l) Swap (L, R);Panax Notoginseng     intt = log[r-l +1]; -     returnMin (F[l][t], F[r-(1<< T) +1][t]); the } +InlinevoidUPDL (intLintRinto) { A     intp =Calc (L, R); theLL t = 1ll * a[p] * (R-p +1) + Sr[l]-Sr[p]; +Answer + = O *T; - } $InlinevoidUPDR (intLintRinto) { $     intp =Calc (L, R); -LL t = 1ll * a[p] * (P-l +1) + Sl[r]-Sl[p]; -Answer + = O *T; the } - intMain () {fi ("1.txt");Wuyi     intn = Read (), Q = Read (), B = sqrt (n); log[0] = -1; the      for(intI=1; i<=n; ++i) { -A[i] =read (); WuBel[i] = (I-1)/B +1; -Log[i] = Log[i >>1] +1; Aboutf[i][0] =i; $     } -      for(intI=1; i<=q; ++i) -Q[I].L = Read (), Q[I].R = Read (), q[i].id =i; -      A      for(intj=1; j<=log[n]; ++j) +          for(intI=1; i+ (1&LT;&LT;J)-1<=n; ++i) theF[I][J] = Min (F[i][j-1], F[i + (1<< (J-1))][j-1]); -      $     inttop =0; the      for(intI=1; i<=n; ++i) { the          while(Top && A[sk[top]] >= a[i]) R[sk[top]] = i, top--; theSk[++top] =i; the     } -      while(top) R[sk[top]] = n +1, Top--; in      for(intI=n; i>=1; --i) { the          while(Top && a[sk[top]] > A[i]) L[sk[top]] = i, top--; theSk[++top] =i; About     } the      while(top) L[sk[top]] =0, Top--; the      the      for(intI=1; i<=n; ++i) Sl[i] = Sl[l[i]] + 1ll * (I-l[i]) *A[i]; +      for(intI=n; i>=1; -i) sr[i] = Sr[r[i]] + 1ll * (R[i]-i) *A[i]; -      theSort (q +1, q + q +1);Bayi     intL =1, r =0; the      for(intI=1; i<=q; ++i) { the          while(L > Q[i].l) L--, updl (L, R,1);//first add in minus!!!  -          while(R < Q[I].R) R + +, UPDR (L, R,1); -          while(L < Q[I].L) UPDL (L, R,-1), L + +; the          while(R > Q[i].r) updr (L, R,-1), R--; theAns[q[i].id] =Answer; the     } the      for(intI=1; i<=q; ++i) -printf"%lld\n", Ans[i]); the     return 0; the}

4540: [Hnoi2016] Sequence

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