461. Ask for the "Hamming distance" of two numbers into binary Hamming Distance

  
 

   
  

  
public class Solution {
   
  

  
 public int HammingDistance(int x, int y) {
   
  

  
int distance = 0;
   
  

  
string sX = Convert.ToString(x, 2);
   
  

  
string sY = Convert.ToString(y, 2);
   
  

  
int maxLength = Math.Max(sX.Length, sY.Length);
   
  

  
 //填充0，使两个字符串右对齐

   
  

  
sX = sX.PadLeft(maxLength, ‘0‘);
   
  

  
sY = sY.PadLeft(maxLength, ‘0‘);
   
  

  

   
  

  
  for    ( int   i  =    0    I  <   MaxLength    I  ++)    {  
   
  

  
if (sX[i] != sY[i]) {
   
  

  
distance++;
   
  

  
}
   
  

  
}
   
  

  

   
  

  
return distance;
   
  

  
 }
   
  

  
}
  
 

From for notes (Wiz)

461. Ask for the "Hamming distance" of two numbers into binary Hamming Distance