Bulls and cows

You is playing the following Bulls and cows game with your friend:you write a 4-digit secret number and ask your friend To guess it, each time your friend guesses a number, you give a hint, the hint tells your friend how many digits is in th e correct positions (called "bulls") and how many digits is in the wrong positions (called "cows"), your friend would use Those hints to find out the secret number.

For example:

Secret Number:  1807Friend ' s guess:7810

Hint: 1 Bull and 3 cows. ( 8 the bull is, the cows 0 is, and 1 7 .)

According to Wikipedia: "Bulls and Cows (also known as cows and Bulls or Pigs and Bulls or Bulls and cleots) are an old cod E-breaking mind or paper and pencil game for-or more players, predating the similar commercially marketed board game M Astermind. The numerical version of the game is usually played with 4 digits, but can also being played with 3 or any other number of Di Gits. "

Write a function to return a hint according to the secret number and friend's guess, use to A indicate the Bulls and c1/> to indicate the cows, in the above example, your function should return 1A3B .

Assume that the secret number and your friend's guess only contain digits, and their lengths is always equal.

My Code 1:

Accepted

public string Gethint (String secret, String guess) {

int len = Secret.length ();
int A = 0;
int B = 0;

char [] se = Secret.tochararray ();
for (int i = 0; i < len; i++)
{
if (se[i] = = Guess.charat (i))
{
a++;
Se[i] = ";
}
}

int []mapa = new INT[10];
int []MAPB = new INT[10];
for (int i = 0; i < len; i++)
{
if (se[i] = = ")
{
Continue
}
Mapa[integer.parseint ("+se[i")]++;
Mapb[integer.parseint ("" +guess.charat (i))]++;
}

for (int i = 0; i <; i++)
{
B + = Math.min (Mapa[i], mapb[i]);
}

Return "" + A + "a" + B + "B";
}

My Code 2:

Accepted
public string Gethintt (String secret, String guess) {


int len = Secret.length ();
int A = 0;
int B = 0;

char [] se = Secret.tochararray ();
char [] gu = Guess.tochararray ();
for (int i = 0; i < len; i++)
{
if (se[i] = = Gu[i])
{
a++;
Se[i] = ";
Gu[i] = ";
}
}
map<character,integer> MapA = new Hashmap<character, integer> ();
map<character,integer> MAPB = new Hashmap<character, integer> ();

for (int i = 0; i< len; i++)
{
if (se[i] = = ")
{
Continue
}
Char key = Se[i];
int value = 1;
if (Mapa.containskey (key))
{
Value + = Mapa.get (key);
}
Mapa.put (key, value);

key = Gu[i];
Value = 1;
if (Mapb.containskey (key))
{
Value + = Mapb.get (key);
}
Mapb.put (key, value);
}

Iterator<character> it = Mapb.keyset (). Iterator ();

while (It.hasnext ())
{
Char key = It.next ();
int value = Mapb.get (key);
if (Mapa.containskey (key))
{
B + = Math.min (value, Mapa.get (key));
Mapa.remove (key);
}
It.remove ();
}
Return "" + A + "a" + B + "B";

}

Bulls and cows