Calculate the distance between two GPS coordinates

Scenario: the longitude and latitude coordinates of two GPS points are known. Calculate the distance between two points.

1.Distance/latitude relationship

GPS: 22.514519, 113.380301

GPS: 22.511962, 113.380301

Distance: 284.6439379583341 

Jl_wd = 284.6439379583341/(22.51451-22.511962)

= 111712.69150641055729984301412873 (meters/degree)

2.Distance/longitude relationship

GPS: 22.514866, 113.388444

GPS: 22.514866, 113.379378

Distance: 932.2997762326453

Jl_jd = 932.2997762326453/(113.388444-113.379378)

= 102834.74258026089786013677476285 (meters/degree)

3. Cut-off Theorem

 

Pythagorean theorem: a2 + b2 = c2

 

 

After knowing the coordinates of A and B, you can obtain the absolute value of the latitude difference between A and B.

Wd_c = | (N1,-N2) |

Absolute Value of the longitude difference between point A and point B

Jd_c = | (E2-E1) |

Knowing the relationship between longitude, latitude and distance, and the longitude difference and latitude difference between point a and point B, you can find the length of B and the length of, after finding a and B, you can use the stock theorem of the straight triangle to find the length of the c side, that is, the distance between point a and point B.

B = wd_c * jl_wd

A = jd_c * jl_jd

C = √ (a2 + b2)

 

C # implementation code:

 

Calculate the distance between two GPS coordinates

/// <Summary>
/// Calculate the distance between two GPS coordinates
/// </Summary>
/// <Param name = "n1"> latitude coordinate of the first point </param>
/// <Param name = "e1"> longitude coordinate of the first vertex </param>
/// <Param name = "n2"> latitude coordinate of the second point </param>
/// <Param name = "e2"> longitude coordinate of the second vertex </param>
/// <Returns> </returns>
Public static double Distance (double n1, double e1, double n2, double e2)
{
Double maid = 102834.74258026089786013677476285;
Double maid = 111712.69150641055729984301412873;
Double B = Math. Abs (e1-e2) * jl_jd );
Double a = Math. Abs (n1-n2) * jl_wd );
Return Math. Sqrt (a * a + B * B ));

}