# Closet number in sorted array

Source: Internet
Author: User

Closest number in Sorted Array

Given a target number and an integer array a sorted in ascending order, find the index in `i` a such that a[i] is closes T to the given target.

Return-1 If there is no element in the array.

Example

Given `[1, 2, 3]` and target = `2` , return `1` .

Given `[1, 4, 6]` and target = `3` , return `1` .

Given `[1, 4, 6]` and target = `5` , return `1` or `2` .

Given `[1, 3, 3, 4]` and target = `2` , return `0` or `1` or `2` .

Note

There can duplicate elements in the array, and we can return any of the indices with same value.

` 1 classSolution {2  Public: 3     /** 4 * @param A integer array sorted in ascending order 5 * @param target an integer 6 * @return A Integer 7*/ 8     intClosestnumber (vector<int>& A,inttarget) { 9         if(a.size () = =0) {Ten             return-1; One         } A          -         intb =0, E = A.size ()-1; -          while(b +1<e) { the             intMid = B + (e-b)/2; -             if(A[mid] = =target) { -                 returnmid; -}Else if(A[mid] <target) { +b =mid; -}Else { +E =mid; A             } at         } -         if(ABS (A[b]-target) < ABS (A[e]-target)) { -             returnb; -}Else { -             returne; -         } in     } -};`

Closet number in sorted array

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