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2016/12/12
1. Gauss's Law (Gauss's Laws): electric field
The electric charge (electic charges) produces a static electric field (static electric field). The electrostatic field line starts at a positive charge and points to a negative charge. The total amount of charge in any area is proportional to the second-type area of the corresponding electric field on the surface of the area. Represented by a formula is $$\int_{\omega} \FRAC{\RHO}{\EPSILON_0}DX = \int_{\partial \omega} \vec{e}\cdot d\vec{s},$$ where $\epsilon_0$ This coefficient of proportionality is called "vacuum permittivity, dielectricity of free space". After the equation is represented by the divergence formula to the right, you get $$\int_{\omega} \FRAC{\RHO}{\EPSILON_0}DX = \int_{\omega} \delta \cdot \vec{e} ~dx.$$ because of the arbitrary nature of $\omega$, We get $$\delta \cdot \vec{e} = \frac{\rho}{\epsilon_0}.$$
2. Gauss's Law (Gauss's Laws): magnetic field
There is no so-called "magnetic charge". The magnetic field lines are all closed. In other words, there is no such a point, so that the magnetic field line from here to the surrounding shot. Expressed in the formula is $$\int_{\omega} \delta \cdot \vec{b}~dx = 0.$$ due to the arbitrary nature of $\omega$, we get $$\delta \cdot \vec{b} = 0.$$
3, Faraday Law of electromagnetic induction (Faraday's Law of induction)
The changing magnetic field generates an electric field, and the electric field of the electric field generated by the changing magnetic field is closed, meaning that the $e$ is not zero. and ampere Law further points out that: the change rate of the magnetic field $b$ is proportional to the spin of the $e$ produced. The formula is expressed as follows $$\delta \times E =-\frac{\partial b}{\partial t}.$$
4, Ampere Law (ampere ' s laws)
Maxwell equations (Maxwell ' s equation)