Binary representation of decimals

Two ways to pay attention to the logical details!

//Title Description////There is a real number between 0 and 1, and the type is double, which returns its binary representation. Returns "Error" if the number cannot be represented exactly in a 32-bit binary representation. //given a double num, which represents a real number from 0 to 1, return a string representing the binary representation of the numbers or "Error". //Test Examples://0.625//return: 0.101//two methods, forward and reverse#include<iostream>using namespacestd; #include<string>classBindecimal { Public:    stringPrintbin (Doublenum) {        //Write code here        Double Base=2.W; stringstr ="0.";  while(num) {if(num>=Base) {num-=Base; STR+="1"; }            Else{str+="0"; }            if(Str.size () >= +) {str="Error";  Break; }    //num-= base; Logic Error            Base=Base/2; }        returnstr; }};classBindecimal { Public:    stringPrintbin (Doublenum) {        //Write code here        stringstr ="0.";  for(inti =0; I < +; i++) {num*=2; if(num>=1) {str+="1"; Num-=1.0; }            Else{str+="0"; }            if(num<=0.0)            {                returnstr; }        }        if(num>0.0)        {            return "Error"; }        returnstr; }};intMain () {Doubleval =0.625;    Bindecimal b; cout<<b.printbin (val) <<Endl; return 0;}

Binary representation of decimals