Java multiple methods for keeping a double two decimal places

Java keeps a double of two decimal places in a multi-method Java reserved Two-bit decimal mport Java.text.DecimalFormat; DecimalFormat DF=NewDecimalFormat ("##### #0. XX"); DoubleD1 =3.23456  DoubleD2 =0.0;DoubleD3 =2.0;d F.format (D1); Df.format (D2); Df.format (D3); 3 results were:3.230.00 2.00java reserved Two-bit decimals problem: Way One: RoundingDoublef =111231.5585; BigDecimal b=NewBigDecimal (f); DoubleF1 = B.setscale (2, bigdecimal.round_half_up). Doublevalue (); Reserved two-bit decimal way two: Java.text.DecimalFormat DF=NewJava.text.DecimalFormat ("#.00"); Df.format (the number you want to format);NewJava.text.DecimalFormat ("#.00"). Format (3.1415926)#.xxrepresents two decimal places #.0000 four decimal places and so on ... Way three:DoubleD =3.1415926; String result= String. Format ("%.2f");%.2f%. Represents any number of digits before the decimal point2The result of representing a two-bit decimal format is F for floating-point mode four: NumberFormat ddf1=numberformat.getnumberinstance ();voidSetmaximumfractiondigits (intdigits) digits displays the number of digits for the formatted object to set the maximum number of digits to display after the decimal point, and the last bit shown is the rounded import java.text.*; import Java.math.* ; classTT { Public Static voidMain (String args[]) {Doublex=23.5455; NumberFormat ddf1=numberformat.getnumberinstance ();dd f1.setmaximumfractiondigits (2); String s=Ddf1.format (x); System. out. Print (s);} }import java.text.*;D Ecimalformat DF=NewDecimalFormat (".##");DoubleD=1252.2563; String St=Df.format (d); System. out. println (ST);

Java multiple methods for keeping a double two decimal places