Pick-up Sticks
Time Limit: 3000MS |
|
Memory Limit: 65536K |
Total Submissions: 11335 |
|
Accepted: 4250 |
Description
Stan has n sticks of various length. He throws them one at a time to the floor in a random. After finishing throwing, Stan tries to find the top sticks, that's these sticks such that there was no stick on top of th Em. Stan has noticed, the last thrown stick was always on top and he wants to know all the sticks that's on top. Stan sticks is very, very thin such that their thickness can be neglected.
Input
Input consists of a number of cases. The data for each case is start with 1 <= n <= 100000, and the number of the sticks for this case. The following n lines contain four numbers each, these numbers is the planar coordinates of the endpoints of one stick. The sticks is listed in the order in which Stan had thrown them. Assume that there is no more than top sticks. The input is ended by the case with N=0. This case is should not being processed.
Output
For each input case, print one line of output listing the top sticks in the format given in the sample. The top sticks should is listed in order in which they were thrown.
The below illustrates the first case from input.
Sample Input
51 1 4 22 3 3 11-2.0 8 41 4 8 23 3 6-2.030 0 1 11 0 2 12 0 3 10
Sample Output
Top Sticks:2, 4, 5.Top sticks:1, 2, 3.
The problem is to find a straight line that is not in line with other lines or on the top of other lines;
Judge the intersection, the two straight line of an endpoint to be judged;
Code:
1#include <iostream>2#include <cstdio>3#include <cstring>4#include <cmath>5#include <algorithm>6 #defineMem (x, y) memset (x,y,sizeof (x))7 using namespacestd;8typedefLong LongLL;9 Const intinf=0x3f3f3f3f;Ten Const intmaxn=100010<<1; One structpoint{ A Doublex, y; -Point (Doublex=0,Doubley=0): X (x), Y (y) {} - }; the typedef point Vector; - Point DT[MAXN]; -Vectoroperator-(point A,point b) {returnVector (a.x-b.x,a.y-b.y);} - DoubleCross (Vector A,vector b) {returna.x*b.y-a.y*b.x;} + intMain () { - intn,k,j; + while(SCANF ("%d",&N), N) { Ak=0; at for(intI=1; i<=n;i++) -scanf"%LF%LF%LF%LF", &dt[i].x,&dt[i].y,&dt[i+n].x,&dt[i+n].y); -printf"Top Sticks:"); - for(intI=1; i<n;i++){ - for(j=i+1; j<=n;j++){ - if(Cross (Dt[i]-dt[j],dt[i]-dt[j+n]) *cross (Dt[i+n]-dt[j],dt[i+n]-dt[j+n]) <=0) in if(Cross (Dt[j]-dt[i],dt[j]-dt[i+n]) *cross (Dt[j+n]-dt[i],dt[j+n]-dt[i+n]) <=0) - Break; to } + if(j==n+1) printf ("%d,", i); - } theprintf"%d.\n", N); * } $ return 0;Panax Notoginseng}
Pick-up sticks (judging the intersection of two lines)