Given a positive integer N, count the number of 1 in a continuous integer ranging from 1 to n.

Source: Internet
Author: User
Int countnumof1 (INT digital)
{
Int num = 0;
While (digital)
{
Num + = (Digital % 10 = 1 )? 1: 0;
Digital/= 10;
}
Return num;
}
Int counttotalnumof1 (int n)
{
Int sum = 0;
Printf ("the first n consecutive numbers are \ n ");
For (INT I = 1; I <= N; ++ I)
{
Printf ("% d", I );
Sum + = countnumof1 (I );
}
Return sum;
}
Int main (void)
{
Int N;
Scanf ("% d", & N );
Printf ("\ N1: % 2D \ n", counttotalnumof1 (n ));
Return 0;
}


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Given a positive integer N, count the number of 1 in a continuous integer ranging from 1 to n.

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