What is your grade? Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)
Total submission (s): 8302 accepted submission (s): 2547
Problem description "point, point, life of Student !"
This is a balglad (Song) well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the rules which are used in this course.
There are 5 problems in this final exam. and I will give you 100 points if you can solve all 5 problems; of course, it is fairly difficulty for your. if you can solve 4 problems, you can also get a high score 95 or 90 (you can get the former (former) only when your rank is in the first half of all students who solve 4 problems ). analogically (and so on), you can get 85, 80, 75, 70, 65, 60. but you will not pass this exam if you solve nothing problem, And I will mark your score with 50.
Note, only 1 student will get the score 95 When 3 students have solved 4 problems.
I wish you all can pass the exam!
Come on!
Inputinput contains multiple test cases. each test case contains an integer N (1 <= n <= 100, the number of students) in a line first, and then n lines follow. each line contains P (0 <= P <= 5 number of problems that have been solved) and T (consumed time ). you can assume that all data are different when 0 <p.
A test case starting with a negative integer terminates the input and this test case shocould not to be processed.
Outputoutput the scores of N students in n lines for each case, and there is a blank line after each case.
Sample Input
45 06:30:174 07:31:274 08:12:124 05:23:1315 06:30:17-1
Sample output
100909095100
This is the first time that WAF has been sweating for 9 times.
#include <cstdio>#include <algorithm>using std::sort;struct Node{int pos, num, s, val;} stu[102];int arr[6];bool cmp1(Node a, Node b){if(a.num == b.num) return a.s < b.s;return a.num > b.num;}bool cmp2(Node a, Node b){return a.pos < b.pos;}int main(){int n, h, m, s, num;while(scanf("%d", &n) == 1 && n > 0){for(int i = 1; i < 6; ++i) arr[i] = 0;for(int i = 0; i < n; ++i){scanf("%d %d:%d:%d", &num, &h, &m, &s);s += m * 60 + h * 3600;stu[i].pos = i;stu[i].num = num;stu[i].s = s;stu[i].val = 100 - (5 - num) * 10;++arr[num];}sort(stu, stu + n, cmp1);for(int i = 4, pos = 0; i; --i){if(arr[i]){while(stu[pos].num != i) ++pos;if(arr[i] == 1) stu[pos++].val += 5;for(int j = 0; j < arr[i] / 2; ++j)stu[pos++].val += 5;}}sort(stu, stu + n, cmp2);for(int i = 0; i < n; ++i)printf("%d\n", stu[i].val);printf("\n");}return 0;}