Description
A number whose only prime factors be 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, ten,, +, (+), A, ten, A, ten, ten, ... shows the first humble numbers.
Write a program to find and print the nth element in this sequence
Input
The input consists of one or more test cases. Each test case consists the one integer n with 1 <= n <= 5842. Input is terminated by a value of zero (0) for N.
Output
For each test case, print one line saying "The nth humble number is number." Depending on the value of n, the correct suffix "st", "nd", "ts", or "th" for the ordinal number nth have to is used like I T is shown in the sample output.
Sample Input
1234111213212223100100058420
Sample Output
The 1st humble number is 1.The 2nd humble number is 2.The 3rd humble number are 3.The 4th humble number is 4.The 11th HUMBL E number is 12.The 12th humble number are 14.The 13th humble number is 15.The 21st humble number is 28.The 22nd humble numb ER is 30.The 23rd humble number is 32.The 100th humble number are 450.The 1000th humble number is 385875.The 5842nd humble Number is 2000000000. Test instructions: There is a number of the qualitative factor is any one or more of the 2,3,5,7, then it is humble number, the number of nth humble. Analysis: If a humble number, then it is certainly a multiple of 2,3,5,7, then A[k]=min (2*B2,3*B3,5*B5,7*B7), and B2,b3,b5,b7 constantly updated, so in order to arrange the
#include <iostream>#include<cstring>#include<cstdio>#include<algorithm>using namespacestd;inta[5850]= {0,1};intMain () {intk=1, N; intB2,b3,b5,b7; B2=b3=b5=b7=1; while(k<=5842) {a[++k]=min (2*a[b2],min (3*a[b3],min (5*A[B5],7*A[b7])); if(a[k]==2*a[b2]) B2++; if(a[k]==3*a[b3]) B3++; if(a[k]==5*a[b5]) B5++; if(a[k]==7*A[b7]) B7++; } while(~SCANF ("%d",&N), N) {if(n%Ten==1&&n% -!= One) printf ("The %dst humble number is%d.\n", N,a[n]); Else if(n%Ten==2&&n% -!= A) printf ("The %dnd humble number is%d.\n", N,a[n]); Else if(n%Ten==3&&n% -!= -) printf ("The %DRD humble number is%d.\n", N,a[n]); Elseprintf ("The %dth humble number is%d.\n", N,a[n]); } return 0;}
View Code
HDU 1058 Humble Numbers