Deformation lesson
Time limit:2000/1000 MS (java/others) Memory limit:131072/65536 K (java/others)
Total submission (s): 18477 Accepted Submission (s): 6666
Problem Description uh ... In the Metamorphosis class Harry ran into a little trouble, because he was not as Hermione as he could remember all the spells and randomly turned a baseball into a hedgehog or something, but he found a uniform rule of Transfiguration spells: If the spell is a word ending with a B, Then it works just to make a object into a B object.
Harry has already made a list of all the spells he has, and he wants you to help calculate whether he can finish the teacher's homework and turn a B (ball) into a M (Mouse), you know, if he can't do it himself, he has to ask Hermione. and was forced to listen to a lot of good learning.
There are multiple sets of input test data. Each group has multiple lines, one word per line, and only lowercase letters, all of which Harry spells. The number 0 indicates the end of a set of inputs.
Output "Yes" If Harry can finish his homework, otherwise output "No." (Do not ignore the period)
Sample Inputsosoonrivergoesthemgotmoonbeginbig0 Sample Outputyes.
HintHintharry can read this mantra: "Big-got-them".
Sourcegardon-dygg Contest 1recommendjgshining | We have carefully selected several similar problems for you:1180 1258 1728 1372 1072
Deep search of the foundation, the last letter of a word if it is the same as the first letter of another word, it can be changed into this word, and judging whether it can be changed from B to M, the letter can be converted into a digital judgment to reduce the difficulty of judging.
Test instructions: Chinese question.
Attached code:
1#include <iostream>2#include <cstdio>3#include <cstring>4 using namespacestd;5 intss[ -][ -],fail;6 7 voidDFS (intk)8 {9 if(fail)Ten return; One if(k=='m'-'a')//find m, end deep search A { -Fail=1; - return; the } - for(intI=0;i< -; i++)//start searching in 26 alphabetical order - { - if(Ss[k][i]) + { -ss[k][i]=0;//the searched mark is 0. + DFS (i); A } at } - } - - intMain () - { - Chars[ -]; in while(~SCANF ("%s", s))//The input must be cycled multiple times - { to if(s[0]=='0'&&strlen (s) = =1) + Break; -memset (SS,0,sizeof(ss)); the intx, y; *x=s[0]-'a';//Convert letters to numbers $Y=s[strlen (s)-1]-'a';Panax Notoginsengss[x][y]=1;//the first letter of each word can be converted with the last letter - while(~SCANF ("%s", s)) the { + if(s[0]=='0'&&strlen (s) = =1)//output 0 jump out of loop A Break; thex=s[0]-'a'; +Y=s[strlen (s)-1]-'a'; -ss[x][y]=1; $ } $Fail=0; -DFS (1);//start with the B-Letter search . - if(fail) printf ("yes.\n"); the Elseprintf"no.\n"); - }Wuyi return 0; the}
HDU 1181 Transformation Course (DFS)