HDU 1272 determines whether the given graph is a spanning tree (and is set)

Source: Internet
Author: User

Judging whether the given graph is a spanning tree, if there is a heavy edge is not, if there is no heavy edge but the connected component is greater than 1 is not

The Find function will overflow with an infinite stack with the previous recursive write Orz

Stack overflow, add this string

#pragma COMMENT (linker, "/stack:1024000000,1024000000")

Sample Input
6 8 5 3 5 2 6 4
5 6 0 0

8 1 7 3 6 2 8 9 7 5
7 4 7 8 7 6 0 0

3 8 6 8 6 4
5 3 5 6 5 2 0 0

-1-1

Sample Output
Yes
Yes
No

1# include <iostream>2# include <cstdio>3# include <cstring>4# include <algorithm>5# include <cmath>6# include <queue>7# define LLLong Long8 using namespacestd;9 Ten Const intmaxn=100010; One intF[MAXN]; A BOOLVIS[MAXN]; - intSAVE[MAXN]; - BOOLFlag; the intFindintx) - { -      while(x!=F[x]) -x=F[x]; +      returnx; - } + voidBingintUintv) A { at     intt1=find (u); -     intT2=Find (v); -     if(T1!=T2) f[t1]=T2; -     ElseFlag =1;//with heavy edges - } - intMain () in { -     //freopen ("In.txt", "R", stdin); to     intu, v; +      while(SCANF ("%d%d", &u, &v)! =EOF) -     { the         if(U = =-1&& v = =-1) *              Break ; $         if(U = =0&& v = =0)Panax Notoginseng         { -printf"yes\n") ; the             Continue ; +         } A          inti; the           for(i=1; i<maxn;i++) +          { -f[i]=i; $          } $memset (Vis,0,sizeof(Vis)); -F[u] =v; -         intL =0 ; theFlag =0 ; -         if(!Vis[u])Wuyi         { theVis[u] =1 ; -save[l++] =u; Wu         } -         if(!Vis[v]) About         { $VIS[V] =1 ; -save[l++] =v; -         } -          while(SCANF ("%d%d", &u, &v)) A         { +             if(U = =0&& v = =0) the                 Break ; -             if(flag) $                 Continue ; the             if(!Vis[u]) the         { theVis[u] =1 ; thesave[l++] =u; -         } in             if(!Vis[v]) the         { theVIS[V] =1 ; Aboutsave[l++] =v; the         } the Bing (u,v); the         } +         intres =0;//Connected Components -          for(i =0; I < L; i++) the             if(F[save[i]] = =Save[i])Bayires++ ; the         if(Res >=2|| Flag = =1) theprintf"no\n") ; -         Else -printf"yes\n") ; the     } the     return 0; the}
View Code

HDU 1272 determines whether the given graph is a spanning tree (and is set)

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