Crazy searchtime limit:5000msmemory limit:32768kbthis problem would be judged onHDU. Original id:1381
64-bit integer IO format: %i64d Java class name: Main Many people like-to-solve hard puzzles some of which, may leads them to madness. One such puzzle could is finding a hidden prime number in a given text. Such number could is the number of different substrings of a given size that exist in the text. As you soon would discover, you really need the "a" computer and a good algorithm to solve such a puzzle.
Your task is to write a program this given the size, N, of the substring, the number of different characters that may OCCU R in the text, NC, and the text itself, determines the number of different substrings of a size N that appear in the text.
As an example, consider n=3, nc=4 and the text "Daababac". The different substrings of size 3 that can being found in this text is: "Daa", "AaB", "ABA", "Bab", "BAC". Therefore, the answer should be 5.
InputThe first line of input consists of a numbers, N and NC, separated by exactly one space. This was followed by the text where the search takes place. Assume that the maximum number of substrings formed by the possible set of characters does is exceed.
OutputThe program should output just a integer corresponding to the number of different substrings of size N found in the given Text.
The first line of a multiple input was an integer N and then a blank line followed by N input blocks. Each input block was in the format indicated in the problem description. There is a blank line between input blocks.
The output format consists of N output blocks. There is a blank line between output blocks.
Sample Input
4daababac
Sample Output
5
Problem solving: very sharp hash Dafa
1#include <iostream>2#include <cstdio>3#include <cstring>4 using namespacestd;5 Const intMAXN =16000010;6 intbs[ the],cnt,n,Base, ans,t;7 Charstr[1000010];8 BOOLHS[MAXN];9 intMain () {Tenscanf"%d",&T); One while(t--) { Ascanf"%d%d%s",&n,&Base, str); - intLen =strlen (str); -memset (HS,false,sizeof(HS)); the for(inti = CNT =0; i < Len; ++i) - if(!Bs[str[i]]) { -Bs[str[i]] = cnt++; - if(CNT = =Base) Break; + } - for(inti = ans =0; i + n <= len; ++i) { +UnsignedintHASHV =0; A for(intj =0; J < N; J + +) atHASHV = hashv*Base+ bs[str[i+J]]; - if(!HS[HASHV]) { -HS[HASHV] =true; -ans++; - } - } inprintf"%d\n", ans); - if(T) puts (""); to } + return 0; -}
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HDU 1381 Crazy Search