HDU 1698 just a hook (line segment tree, segment update)

Just a hook

Time Limit: 4000/2000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)
Total submission (s): 9258 accepted submission (s): 4510

Problem descriptionin the game of Dota, Pudge's meat hook is actually the most horrible thing for most of the heroes. the hook is made up of several consecutive metallic sticks which are of the same length.

Now Pudge wants to do some operations on the hook.

Let us number the consecutive metallic sticks of the hook from 1 to n. for each operation, Pudge can change the consecutive metallic sticks, numbered from X to Y, into cupreous sticks, silver sticks or golden sticks.
The total value of the hook is calculated as the sum of values of N metallic sticks. More precisely, the value for each kind of stick is calculated as follows:

For each cupreous stick, the value is 1.
For each silver stick, the value is 2.
For each golden stick, the value is 3.

Pudge wants to know the total value of the hook after creating the operations.
You may consider the original hook is made up of cupreous sticks.

 

Inputthe input consists of several test cases. The first line of the input is the number of the cases. There are no more than 10 cases.
For each case, the first line contains an integer N, 1 <=n <= 100,000, which is the number of the sticks of Pudge's meat hook and the second line contains an integer Q, 0 <= q <= 100,000, which is the number of the operations.
Next Q lines, each line contains three integers x, y, 1 <= x <= Y <= N, Z, 1 <= z <= 3, which defines an operation: change the sticks numbered from X to Y into the metal kind Z, where z = 1 represents the cupreous kind, Z = 2 represents the silver kind and Z = 3 represents the golden kind.

 

Outputfor each case, print a number in a line representing the total value of the hook after the operations. Use the format in the example.

 

Sample input1 10 2 1 5 2 5 9 3

 

Sample outputcase 1: the total value of the hook is 24.

 

Source2008 "sunline Cup" national invitational contest

 

The recommendwangye line segment tree is mainly an update method. It cannot be directly updated to the bottom. It must be updated in segments and the lazy flag is added.

 /*  Segment update of HDU 1689 Line Segment  */  # Include <Stdio. h> # Include < String . H> # Include <Algorithm> # Include <Iostream> Using   Namespace  STD; Const   Int Maxn = 100010  ;  Struct  Node {  Int  L, R;  Int  Lazy, tag;  Int  SUM;} segtree [maxn * 3  ];  Void Build ( Int I,Int L, Int  R) {segtree [I]. L = L; segtree [I]. r = R; segtree [I]. Lazy = 0  ; Segtree [I]. Tag = 0  ;  If (L = R) {segtree [I]. Sum = 1  ;  Return ;}  Int Mid = (L + r)> 1  ; Build (I < 1  , L, mid); Build (I < 1 ) | 1 , Mid + 1  , R); segtree [I]. Sum = Segtree [I < 1 ]. Sum + segtree [(I < 1 ) | 1  ]. Sum ;} Void Update ( Int I, Int L, Int R, Int  V ){  If (Segtree [I]. L = L & segtree [I]. r = r) //  Segment update  {Segtree [I]. Lazy = 1  ; Segtree [I]. Tag = V; segtree [I]. Sum = (R-l +1 )* V;  Return  ;}  Int Mid = (segtree [I]. L + segtree [I]. R)> 1  ;  If (Segtree [I]. Lazy = 1  ) {Segtree [I]. Lazy = 0  ; Update (I < 1  , Segtree [I]. l, mid, segtree [I]. Tag); Update (I < 1 ) | 1 , Mid + 1  , Segtree [I]. R, segtree [I]. Tag); segtree [I]. Tag = 0  ;}  If (R <= mid) Update (I < 1  , L, R, V );  Else   If (L> mid) Update (I < 1 ) | 1  , L, R, V ); Else  {Update (I < 1  , L, mid, V); Update (I < 1 ) | 1 , Mid + 1  , R, V);} segtree [I]. Sum = Segtree [I < 1 ]. Sum + segtree [(I < 1 ) | 1  ]. Sum ;}  Int  Main (){ //  Freopen ("in.txt", "r", stdin );  //  Freopen ("out.txt", "W", stdout );      Int  X, Y, Z;  Int  N;  Int  M;  Int  T; scanf (  "  % D  " ,& T ); Int Icase = 0  ;  While (T -- ) {Icase ++ ; Scanf (  "  % D  " , & N ,& M); Build (  1 , 1  , N );  While (M --) {Scanf (  "  % D  " , & X, & Y ,& Z); Update (  1  , X, y, z);} printf (  "  Case % d: the total value of the hook is % d. \ n  " , Icase, segtree [ 1  ]. Sum );}  Return   0  ;}