Keywords SearchTime
limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)
Total submission (s): 40414 Accepted Submission (s): 12885
Problem DescriptionIn The modern time, Search engine came into the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring the feature to his image retrieval system.
Every image has a long description, when users type some keywords to find the image, the system would match the keywords W ITH description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords would b E match.
Inputfirst line would contain one integer means how many cases would follow by.
Each case would contain integers n means the number of keywords and n keywords follow. (N <= 10000)
Each keyword would only contains characters ' a '-' Z ', and the length would be is not longer than 50.
The last line is the description, and the length would be a not longer than 1000000.
Outputprint How many keywords is contained in the description.
Sample Input
15shehesayshrheryasherhs
Sample Output
3
Hey, look at the AC automata theory for a long time, and then look at the template code, and finally a little thorough understanding of AC automata.
AC Automata theory: http://blog.csdn.net/niushuai666/article/details/7002823
Code:
#include <cstdio> #include <cstdlib> #include <cstring> #include <queue> #define SIZE 1000100using namespace std; struct trie{int count; Trie *fail; Trie *next[26]; Trie () {for (int i = 0; i <; ++i) next[i] = null; fail = NULL; count = 0;}} *root; char des[size]; void Insert (char ch[]) {int len = strlen (CH); Trie *t = root; for (int i = 0; i < len; ++i) {if (t->next[ch[i]-' a '] = = NULL) {t->next[ch[i]-' a '] = new Trie ();} t = t->next[ch[i]-' a '];} t->count++;} void BFs () {queue<trie*> que; Que.push (root), while (!que.empty ()) {Trie *t = Que.front (), Que.pop (); for (int i = 0; i < 26; ++i) {if (T->next[i]! = NULL) {if (t = = root) T->next[i]->fail = root; Else{trie *p = T->fail; while (p) {if (p-> Next[i]) {t->next[i]->fail = p->next[i]; break;} p = p->fail;} if (p = = NULL) T->next[i]->fail = root;} Que.push (T->next[i]);}}} int query (char str[]) {int sum = 0, i = 0; Trie *now = root, while (Str[i]) {int pos = str[i]-' A ' ; while (now->next[pos] = = NULL && now! = root) {now = Now->fail;} now = Now->next[pos]; if (!now) now = root; Trie *temp = Now, while (temp! = root) {if (temp->count>=0) {sum + = Temp->count; temp->count =-1;} else break; temp = Temp->fail; }++i;} return sum; }void del (Trie *t) {for (int i = 0; i <; ++i) {if (T->next[i]) del (t->next[i]);} Free (t);} int main () {int t; scanf ("%d", &t), while (t--) {root = new Trie (); int n; scanf ("%d", &n); GetChar (); for (int i = 0; i < n; ++i) {char str[100]; gets (str); insert (str);} BFS (), gets (des), int ans = query (des);p rintf ("%d\n", ans);d El (root);} return 0;}
with June
HDU 2222 Keywords Search ac automaton template problem