Topic Connection
http://acm.hdu.edu.cn/showproblem.php?pid=2425
Hiking Tripdescription
Hiking in the mountains is seldom a easy task for most people, as it's extremely easy-to-get lost during the trip. Recently Green has decided to go on a hiking trip. Unfortunately, half through the trip, he gets extremely tired and so needs to find the path that would bring him to the Destination with the least amount of time. Can you help him?
You ' ve obtained the area Green's in as a R * C map. Each grid in the map can is one of the four types:tree, sand, path, and stone. All grids not containing stone is passable, and each time, when Green enters a grid of type X (where X can is tree, sand or path), he'll spend time T (X). Furthermore, each time Green can only move up, down, left, or right, provided that the adjacent grid in that direction Exi Sts.
Given Green's current position and he destination, please determine the best path for him.
Input
There is multiple test cases in the input file. Each test case starts with integers R, C (2 <= R <=, 2 <= C <=), the number of Rows/columns DESCRI Bing the area. The next line contains three integers, VP, VS, VT (1 <= VP <=, 1 <= VS <=, 1 <= VT <=), Deno Ting The amount of time it requires to walk through the three types of area (path, sand, or tree). The following R lines describe the area. Each of the R lines contains exactly C characters, each character being one of the following: ' T ', '. ', ' # ', ' @ ', CORRESPO Nding to grids of type tree, sand, path and stone. The final line contains four integers, sr, SC, TR, TC, (0 <= SR < R, 0 <= SC < C, 0 <= TR < R, 0 <= T C < c), representing your current position and your destination. It is guaranteed that Green's current position is reachable–that are to say and it won ' t be a ' @ ' square.
There is a blank line after each test case. Input ends with End-of-file.
Output
For each test case, output one integer in one separate line, representing the minimum amount of time needed to complete th E trip. If there is no-on-Green to reach the destination, output-1 instead.
Sample Input
4 6
1 2 10
T... Tt
ttt###
[Email protected] #T
.. ###@
0 1 3 0
4 6
1 2 2
T... Tt
ttt###
[Email protected] #T
.. ###@
0 1 3 0
2 2
5 1 3
[Email protected]
@.
0 0 1 1
Sample Output
Case 1:14
Case 2:8
Case 3:-1
Bfs+ Priority queue:
1#include <algorithm>2#include <iostream>3#include <cstdlib>4#include <cstring>5#include <cstdio>6#include <vector>7#include <queue>8#include <map>9 usingstd::cin;Ten usingstd::cout; One usingStd::endl; A usingStd::find; - usingStd::sort; - usingStd::map; the usingstd::p air; - usingstd::vector; - usingStd::multimap; - usingstd::p riority_queue; + #definePB (E) push_back (e) - #defineSZ (c) (int) (c). Size () + #defineMP (A, b) Make_pair (A, B) A #defineAll (c) (c). Begin (), (c). End () at #defineITER (c) Decltype ((c). Begin ()) - #defineCLS (arr,val) memset (arr,val,sizeof (arr)) - #defineCpresent (c, E) (Find (All (c), (e))! = (c). End ()) - #defineRep (i, n) for (int i = 0; i < (int) (n); i++) - #defineTR (c, I) for (ITER (c) i = (c). Begin (); I! = (c). end (); ++i) - Const intN = the; intypedef unsignedLong Longull; - BOOLVis[n][n]; to CharTrip[n][n]; + Const intDx[] = {0,0, -1,1}, dy[] = {-1,1,0,0 }; - intR, C, Vs, Vp, Vt, Sx, Sy, Dx, Dy; the structNode { * intx, y, S; $Node (inti =0,intj =0,intK =0): X (i), Y (j), S (k) {}Panax NotoginsengInlineBOOL operator< (ConstNode &a)Const { - returns >A.S; the } + }; A intBFs () { theCLS (Vis,false); +Priority_queue<node>que; -Que.push (Sx, Sy,0)); $Vis[sx][sy] =true; $ while(!Que.empty ()) { -Node tmp =que.top (); Que.pop (); - if(tmp.x = = Dx && tmp.y = = Dy)returnTmp.s; theRep (I,4) { - intNX = Dx[i] + tmp.x, NY = dy[i] +tmp.y;Wuyi Char&ch =Trip[nx][ny]; the if(NX <0|| NX >= R | | NY <0|| NY >= C)Continue; - if(ch = ='@'|| Vis[nx][ny])Continue; Wu if(ch = ='T') Que.push (Node (NX, NY, TMP.S +Vt)); - Else if(ch = ='.') Que.push (Node (NX, NY, TMP.S +Vs)); About Else if(ch = ='#') Que.push (Node (NX, NY, TMP.S +Vp)); $Vis[nx][ny] =true; - } - } - return-1; A } + intMain () { the #ifdef LOCAL -Freopen ("In.txt","R", stdin); $Freopen ("OUT.txt","w+", stdout); the #endif the intK =1; the while(~SCANF ("%d%d", &r, &C)) { thescanf" %d%d%d", &VP, &vs, &Vt); -Rep (i, R) scanf ("%s", Trip[i]); inscanf"%d %d%d%d", &SX, &sy, &DX, &Dy); theprintf"Case %d:%d\n", k++, BFS ()); the } About return 0; the}
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Hdu 2425 Hiking Trip