KiKi ' s K-numberTime
limit:$ MS
Memory Limit:32768KB
64bit IO Format:%i64d &%i64u SubmitStatusPracticeHDU 2852Appoint Description:Leolin (2011-08-22)System Crawler (2015-04-16)
Description
For the k-th number, we all should is very familiar with it. of Course,to Kiki it is also simple. Now Kiki meets a very similar problem, Kiki wants to design a container, the container are to support the three operations.
Push:push a given element e to container
Pop:pop element of a given e from container
Query:given elements A and K, query the kth larger number which greater than a in container;
Although Kiki is very intelligent, she can isn't think of how to does it, can you help hers to solve this problem?
Input
Input Some groups of test data, each test data the first number is a integer m (1 <= m <100000), means that the NUM ber of operation to do. The next m lines, each line would be a integer p at the beginning, p which have three values:
If p is 0 and then there'll be a integer e (0 <e <100000), means press element e into Container.
If p is 1 and then there'll be a integer e (0 <e <100000), indicated that delete the element e from the container
If P is 2, then there'll be integers a and K (0 <a <100000, 0 <k <10000), means the inquiries, the Elemen T is greater than a, and the k-th larger number.
Output
For each deletion, if want to delete the element which does not exist, the output "No elment!". For each query, the output of the suitable answers in line. If the number is does not exist, the output is "not find!".
Sample Input
Sample Output
No Elment!6not Find!224not find!
#include <stdio.h> #include <math.h> #include <string.h> #include <stdlib.h> #include < iostream> #include <sstream> #include <algorithm> #include <set> #include <queue> #include <stack> #include <map>using namespace std;typedef long long ll;const int inf=0x3f3f3f3f;const double pi= ACOs ( -1.0); #define Lson l,mid,rt<<1#define rson mid+1,r,rt<<1|1const int maxn=100010;int sum[maxn<<2]; void pushup (int rt) {sum[rt]=sum[rt<<1]+sum[rt<<1|1];} void Update (int p, int x, int l, int r, int rt) {if (l==r) {sum[rt]+=p; return; } int mid= (L+R) >>1; if (x<=mid) Update (p, X, Lson); Else Update (p, X, Rson); Pushup (RT);} int Query (int ll, int rr, int l, int r, int rt) {if (ll<=l&&rr>=r) {return SUM[RT]; } int mid=l+r>>1; int ans=0; if (ll<=mid) ans+=query (Ll,rr,lson); if (rr>mid) ans+=query (Ll,rr,rson); return ans;} int binsearch (int k) {int high=100010, low =1, mid; int ans=-1; int res; while (Low<=high) {mid= (Low+high) >>1; Res=query (1,mid,1,100010,1); if (res>=k) {high=mid-1; Ans=mid; } else if (res<k) {low=mid+1; }} return ans; int main () {int n,i; int p,a,k; while (~SCANF ("%d", &n)) {memset (sum,0,sizeof (sum)); while (n--) {scanf ("%d", &p); if (p==0) {scanf ("%d", &a); Update (1,a,1,100010,1); } else if (p==1) {scanf ("%d", &a); if (! Query (a,a,1,100010,1)) {printf ("No elment!\n"); Continue; } Update ( -1,a,1,100010,1); } else {scanf ("%d%d", &a,&k); int S=query (1,a,1,100010,1); int Ans=binsearch (S+K); if (ans==-1) printf ("Not find!\n"); else printf ("%d\n", ans); }}} return 0;}
HDU 2852-kiki ' s K-number (segment tree)