http://acm.hdu.edu.cn/showproblem.php?pid=3446
Test instructions: A chessboard, there is a king, some can go to the point, every time can only go to the place, no way to lose, to determine whether the win.
Idea: First remove the location of king, only consider the other, if the matching number and the number of King to find the same, that the location of the king is not in the match, so the hand win, otherwise the initiator win, why?
Can think about, the matching path is a: matching, mismatch, matching ... Mismatch, matching, so if King is in the match, then the last step can also be the initiator to go.
#include <cstdio>#include<cmath>#include<cstring>#include<iostream>#include<algorithm>intdx[]={-1,-1,-1,1,1,1,0,0,2,-2,2,-2,2,-2,2,-2,1,-1,-1,1};intdy[]={-1,1,0,0,1,-1,-1,1,2,2,-2,-2,1,-1,-1,1,2,-2,2,-2};intmatch[ -],g[ -][ -],inpath[ -],q[ -],head,tail,newbase;intinqueue[ -],inblossom[ -],Base[ -],father[ -],n;intfinish,start,r,c,kx,ky,c[ -];Chars[ -][ -];intRead () {intt=0, f=1;CharCh=GetChar (); while(ch<'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} while('0'<=ch&&ch<='9') {t=t*Ten+ch-'0'; ch=GetChar ();} returnt*F;}intLcaintUintv) {memset (Inpath,0,sizeofInpath); while(1) {u=Base[u]; Inpath[u]=1; if(!match[u]) Break; U=Father[match[u]]; } while(1) {v=Base[v]; if(Inpath[v]) Break; V=Father[match[v]]; } returnv;}voidResetintu) { while(u!=newbase) { intv=Match[u]; inblossom[Base[V]] =inblossom[Base[U]] =1; U=Father[v]; if(Base[U]!=newbase] Father[u]=v; }}voidBlossomcontract (intUintv) {Newbase=LCA (U,V); memset (Inblossom,0,sizeofInblossom); Reset (U); Reset (v); if(Base[U]!=newbase] Father[u]=v; if(Base[V]!=newbase] Father[v]=u; for(intI=1; i<=n;i++) if(inblossom[Base[i]]) { Base[i]=newbase; if(!inqueue[i]) c[++tail]=i,inqueue[i]=1; }}voidFindaugmentingpath () {memset (Inqueue,0,sizeofinqueue); memset (father,0,sizeoffather); for(intI=1; i<=n;i++)Base[i]=i; Head=1; tail=1; c[1]=start;inqueue[start]=1; Finish=0; while(head<=tail) { intu=c[head++]; for(intv=1; v<=n;v++) if(g[u][v]&&Base[u]!=Base[v]&&match[v]!=u) { if(v==start| | (match[v]>0) && (father[match[v]]>0) {blossomcontract (u,v); }Else if(father[v]==0) {Father[v]=u; if(Match[v]) {c[++tail]=match[v];inqueue[match[v]]=1; }Else{Finish=v; return; } } } }}voidAugmentpath () {intu,v,w; U=finish; while(u>0) {v=Father[u]; W=Match[v]; Match[u]=v; MATCH[V]=u; U=W; }}intsolve () {intres=0; memset (Match,0,sizeofmatch); for(intI=1; i<=n;i++) if(!Match[i]) {Start=i; Findaugmentingpath (); if(finish) Augmentpath (), res++; } returnRes;}intMain () {intT=read (), tcase=0; while(t--) {printf ("Case #%d:daizhenyang",++Tcase); R=read (); C=read (); memset (G,0,sizeofG); for(intI=1; i<=r;i++) {scanf ("%s", s[i]+1); } for(intI=1; i<=r;i++) for(intj=1; j<=c;j++) if(s[i][j]!='#'){ for(intk=0;k< -; k++){ intx=i+dx[k],y=j+Dy[k]; if(x>=1&&x<=r&&y>=1&&y<=c&&s[x][y]!='#') {g[(i-1) *c+j][(x1) *c+y]=1; g[(x-1) *c+y][(I-1) *c+j]=1; } } if(s[i][j]=='K') kx=i,ky=J; } N=r*b; intt1=solve (); intX= (kx-1) *c+KY; for(intI=1; i<=n;i++)if(G[x][i]) g[x][i]=g[i][x]=0; if(Solve () ==t1) puts ("lose"); ElsePuts"win"); } return 0;}
HDU 3446 Daizhenyang ' s chess