hdu1308 What Day is it__ water problem

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The main topic describes a slight pit is the 1752.9.2 ago the United States date with the old algorithm, 9.14 after the new algorithm

The other 1.1.1 is what setup is for Saturday. The number of days needed to be reduced by 2

Lunar Date =year*365+m[month]+day+year/4-2

New Calendar Date =year*365+year/4-year/100+year/400+m[month]+day+1752/100-1752/400-11-2

=year*365+year/4-year/100+year/400+m[month]+day

February written fabruary half a day did not see it.

Code:

#include <iostream>
#include <cstdio>
using namespace Std;
int mm[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int m[12]={0,31,59,90,120,151,181,212,243,273,304,334};
Char mn[12][20]={"January", "February", "March", "April", "may", "June", "July", "August", "September", "October", " November "," December "};
Char dn[7][20]={"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"};
BOOL Leapyear (int y) {
if (y<=1752)
return y%4==0;
Return ((y%4==0) && (y%100!=0) | | y%400==0;
}
BOOL IsValid (int y,int m,int d) {
if (!m| |! d| |! Y
return 0;
if (m>12)
return 0;
if (y==1752&&m==9&&d>2&&d<14)
return 0;


if (Leapyear (y)) {
if (m==2) {
if (d>29)
return 0;
}
else if (D>mm[m-1])
return 0;
}
else if (D>mm[m-1]) {
return 0;
}
return 1;
}








int main ()
{
Freopen ("Input.txt", "R", stdin);
int y,m,d;
int totday,curday;
while (cin>>m>>d>>y,m| | d| | Y) {


if (!isvalid (y,m,d)) {
printf ("%d/%d/%d is a invalid date.\n", m,d,y);
Continue
}


if (y<1752| | (y==1752&&m<9) | | (y==1752&&m==9&&d<=2)) {
Totday= (y-1) *365+ (y-1)/4;//-(y-1)/100+ (y-1)/400;
TOTDAY+=M[M-1];
Totday+=d;
if (y%4==0&&m>2) {
totday++;
}
totday-=2;
curday=totday%7;
}
else{
Totday= (y-1) *365+ (y-1)/4-(y-1)/100+ (y-1)/400;
Totday+=m[m
-1];
Totday+=d;
if (Leapyear (y) &&m>2) {
totday++;
}
curday=totday%7;
}
if (curday==0)
curday=7;
cout<<curday<<endl;
printf ("%s%d,%d is a%s\n", mn[m-1],d,y,dn[curday-1]);
}
return 0;
}