hdu3572 task allocation/maximum flow inference full flow

Source: Internet
Author: User

Serie A championship: the task of assigning N m machine. To the number of days each task takes (if not ongoing daily) and can be done on which day tasks. Ask if there is a plan.

The typical task (X)----Day (Y) Half of the maximum traffic (because this task is the relationship between days) of the processor control flow. SOURCE X Ministry of Foreign Affairs Point, it refers to a few days. Task Xi, in order to be able to do even if the day, Stream 1, a Y point to the sink point to the flow of M, indicating that day up to use M machine.

PS: note the output format

#include <iostream> #include <queue> #include <cstdio> #include <cstring>using namespace std; const int Inf=0x3f3f3f3f;const int maxv=1001,maxe=200101;int nume=0;int head[maxv];int e[maxe][3];void inline adde (int i    , int j,int c) {e[nume][0]=j;e[nume][1]=head[i];head[i]=nume;    E[nume++][2]=c;    E[nume][0]=i;e[nume][1]=head[j];head[j]=nume; e[nume++][2]=0;}    int Ss,tt,n,m,all;int vis[maxv];int Lev[maxv];bool BFS () {for (int i=0;i<maxv;i++) vis[i]=lev[i]=0;    queue<int>q;    Q.push (ss);    Vis[ss]=1;        while (!q.empty ()) {int Cur=q.front ();        Q.pop ();            for (int i=head[cur];i!=-1;i=e[i][1]) {int v=e[i][0];                if (!vis[v]&&e[i][2]>0) {lev[v]=lev[cur]+1;                Vis[v]=1;            Q.push (v); }}} return VIS[TT];} int dfs (int u,int minf) {if (u==tt| |    minf==0) return minf;    int sumf=0,f; for (int i=head[u];i!=-1&&minf;i=e[i][1]) {int v=e[i][0];            if (lev[v]==lev[u]+1&&e[i][2]>0) {F=dfs (v,minf<e[i][2]?minf:e[i][2]);            E[i][2]-=f;e[i^1][2]+=f;        Sumf+=f;minf-=f;    }} if (!SUMF) lev[u]=-1; return SUMF;}    int dinic () {int sum=0;    while (BFS ())) Sum+=dfs (Ss,inf); return sum;}    void Read_build () {int pi,si,ei;        for (int i=1;i<=n;i++) {scanf ("%d%d%d", &pi,&si,&ei);        All+=pi;        Adde (SS,I,PI);        for (int j=si;j<=ei;j++) {adde (i,n+j,1);    }} for (int i=1;i<=500;i++) {adde (i+n,tt,m);    }}void init () {scanf ("%d%d", &n,&m);    nume=0;all=0;    memset (head,-1,sizeof (head)); ss=n+501;tt=n+502;}    int main () {int T;    scanf ("%d", &t); int ct=1;        while (t--) {init ();        Read_build ();        int Ans=dinic ();        if (ans==all) printf ("Case%d:yes\n\n", ct++);    else printf ("Case%d:no\n\n", ct++); }}



hdu3572 task allocation/maximum flow inference full flow

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