How do I identify a char array character element, split a string character, and show it in parallel?

Array let's take a look at the ToCharArray () and Split () methods because it's related to the problem.

First look at the ToCharArray () method, which copies the characters from this instance to a Unicode character array, which belongs to a string class method that converts a string back to an array of characters, such as:

String Str= "This is";

Char[] arr;

Arr=str. ToCharArray ();//Separates "This is string" as a single character and becomes an element of a char array

If we want to output a look (suppose there is a ListBox control) the method is as follows:

foreach (char[] C in arr)

{

LISTBOX1.ITEMS.ADD (C.tostring ());

}

The result is this:

T

H

I

S



I

S

Looking at this result, you can see that the elements including the spaces are separated into the char array.

Let's look at the Split () method:

The Split () method identifies substrings in this instance that are delimited by one or more characters specified in the array, and then puts those substrings into a string array.

It has two overloaded versions:

Public string[] Split (params char[]);

And

Public string[] Split (char[], int);

We talk about the first version, and the latter version is explained in MSDN.

Its argument is a char[] array, which is the identity of the element in char[] as the partition, and the segmented result is stored in the string[] array, for example:

String stra= "What is this?,oh,orange!";

String[] ARSTR;

Arstr=stra.split (str. ToCharArray ());//str is the "This is" that we defined earlier

The elements in the arstr[] array are the elements that are created after the stra character is identified by 7 characters in Str

Let's take a look at the results as examples:

Foreach (String cc in ARSTR)

{

LISTBOX1.ITEMS.ADD (CC. ToString ());

}

The result is:

Wa







?, O

, orange!

String[] An array of arstr characters that have elements in a arr array do not appear because they are used as split identifiers.

At this point, you may understand the character segmentation and the relationship between the array, if it is, I will be satisfied!