How to calculate the maximum value of the unsigned int and the maximum value of the int on a 32-bit Machine

Source: Internet
Author: User

Copy codeThe Code is as follows: # include <stdio. h>
Int main (int argc, char * argv [])
{
Unsigned int max_int = 0-1;
Printf ("The max value of unsigned int on 32 machine: % u/n", max_int );
}

Copy codeThe Code is as follows: # include <stdio. h>
Int main (int argc, char * argv [])
{
Unsigned int max_int = 0-1;
Printf ("The max value of unsigned int on 32 machine: % u/n", max_int );
}

After gcc Compilation:
Int_sizeof1.c: In the 'main' function:
Int_sizeof1.c: 5: Warning: Integer Overflow
After running:
The max value of int on 32 machine: 4294967295

After VC6.0 and java are compiled, there is no error.
After running:
The max value of int on 32 machine: 4294967295Copy codeThe Code is as follows: # include <stdio. h>
Int main (int argc, char * argv [])
{
Int max_int = (1 <31)-1;
Printf ("The max value of int on 32 machine: % d/n", max_int );
}

The program that writes its int into a signed type is as follows:
Copy codeThe Code is as follows: # include <stdio. h>
Int main (int argc, char * argv [])
{
Int max_int = (1 <31)-1;
Printf ("The max value of int on 32 machine: % d/n", max_int );
}

After gcc Compilation:
Int_sizeof1.c: In the 'main' function:
Int_sizeof1.c: 5: Warning: Integer Overflow
After running:
The max value of int on 32 machine: 2147483647
After VC6.0 and java are compiled, there is no error.
After running:
The max value of int on 32 machine: 2147483647
Because the highest bit of the int is the symbol bit.

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