Http post xml data

I wrote an article about httppost.ArticleHttp://www.cnblogs.com/qidian10/archive/2011/06/20/2085341.html

This articleCodeIn fact, it is a bit of a problem: the first time the data is submitted, it will not pass, and then try again is no problem, it has been puzzled, until today on the msdn found a solution, paste the code below:

Protected String Httppostdata ( String URL, String Strparm, Int Outtime)
{
Stringbuilder Str = New Stringbuilder ();
Try
{
Httpwebrequest wrequest;
Httpwebresponse wresponse = Null ;
Httpwebresponse response = Null ;
// Preauth the request
// You can add logic so that you only pre-authenticate the very first request.
// You shoshould not have to pre-authenticate each request.
Uri URI = New Uri (URL );
Wrequest = (Httpwebrequest) httpwebrequest. Create (URI );
Wrequest. Credentials = New Networkcredential ( " Wcadmin " , " Wcadmin " );
Wrequest. preauthenticate = True ;
Wrequest. useragent = " Upload PLM XML " ;
Wrequest. Method = " Head " ;
Wrequest. Timeout = Outtime;
Wresponse = (Httpwebresponse) wrequest. getresponse ();
Wresponse. Close ();
// Make the real request.
Wrequest = (Httpwebrequest) httpwebrequest. Create (URL );
Wrequest. Credentials = New Networkcredential ( " Wcadmin " , " Wcadmin " );
Wrequest. preauthenticate = True ;
Wrequest. useragent = " Upload PLM XML " ;
Wrequest. Method = " Post " ;
Wrequest. allowwritestreambuffering = False ;
Wrequest. Timeout = 10000 ;
Byte [] postbytes = Encoding. utf8.getbytes (strparm );
Wrequest. contentlength = Postbytes. length;
Stream requeststream = Wrequest. getrequeststream ();
Requeststream. Write (postbytes, 0 , Postbytes. Length );
Requeststream. Close ();
Try
{
Response = (Httpwebresponse) wrequest. getresponse ();
}
Catch (Webexception E)
{
Response = (Httpwebresponse) E. response;
}
Stream responsestream = Response. getresponsestream ();
Streamreader = New Streamreader (responsestream, encoding. Default );
While (Streamreader. Peek () ! = - 1 )
{
Str. append (streamreader. Readline ());
}
Streamreader. Close ();
Response. Close ();
Wresponse. Close ();
}
Catch (Exception error)
{
Str. appendline (error. Message );
}
Return Str. tostring ();
}

Note that you can use this method to submit data in the English comments without encountering an inexplicable error 400.

If the problem persists, refer to the following code.

Http://www.cnblogs.com/hyl8218/archive/2011/07/04/2097394.html

There are two methods to add the HTTP basic authentication information to the request when sending the request:

• First, add authorization to the Request Header:
  Authorization: "basic user name and passwordBase64Encrypted string"
• The second is to add the user name and password to the URL:
  Http ://Username: password @Api.minicloud.com.cn/statuses/friends_timeline.xml

The following shows the implementation code for the first language that adds the Authorization header to the request.

First look at. Net:

 String  Username  =  "  Username "  ;
  String  Password  =  "  Password  "  ;
  //  Note that the format here is "username: Password"  
  String  Usernamepassword  =  Username  +    "  :  "     +  Password;
Credentialcache mycache  =     New  Credentialcache ();
Mycache. Add (  New  Uri (URL ),  "  Basic  "  , New  Networkcredential (username, password ));
Myreq. Credentials  =  Mycache;
Myreq. headers. Add (  "  Authorization  "  ,  "  Basic  "     +  Convert. tobase64string (  New Asciiencoding (). getbytes (usernamepassword )));

Webresponse WR  =  Myreq. getresponse ();
Stream receivestream  =  Wr. getresponsestream ();
Streamreader  =     New  Streamreader (receivestream, encoding. utf8 );
  String  Content  =  Reader. readtoend (); 

You can also use httpwebrequest or other classes to send requests.