Huawei OJ Platform--hundred money to buy hundred chicken problem

Title Description:

Yuanmai Fifth century, the ancient Chinese mathematician Zhang Chujian in the Book of "The Hundred Chicken Problem": the chicken Weng A value of five, chicken mother a valuable three, chickens three valuable one.

Hundred money buys hundred chicken, asks the chicken Weng, the chicken mother, chickens each geometry?

Ideas:

This question is very simple, suppose the chicken Weng I only, chicken mother J only, then has

1. i + j + k = 100
2. 5*i + 3*j + K/3 = 100

By the above two equations we can launch:

1. j = 25-i * 7/4;
2. K = 3/4 + i *;

Because I, j, K must be 0 or a positive integer, so I must be a multiple of 4, so we are in the following program is a 4-step growth

1  Public classBuyhens {2 3      Public Static voidMain (string[] args) {4         inti = 0 ;5         intj = 0 ;6         intK = 0 ;7         8          for(i = 0; 5*i <=; i + = 4){9j = 25-I*7/4 ;TenK = + I*3/4 ; One             //conditions are met J >= 0 && k >= 0 A             if(J >= 0 && k >= 0 ){ -SYSTEM.OUT.PRINTLN (i + "" + j + "" +k); -             }             the         }     -     } -}

Huawei OJ Platform--hundred money to buy hundred chicken problem