[Ideas] Hdu 5414 CRB and String

Test instructions

Give s,t two strings, you can choose to add a character after a character in the S string indefinitely, but the added character cannot be the same as the selected character, ask if the S string can become a T-string.

Ideas:

It was observed that if S is the same as the T length, it is directly sentenced.

If it's not the same, just meet

1. The order of all the characters in S is in the T-string.

2. The same character in front of T and the first part of S can match

Here are two conditions that can be constituted.

Code:

#include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <
algorithm> #include <iostream> #include <stack> using namespace std;
#define LL __int64 Char x[123456],y[123456];
    int main () {int t;
    cin>>t;
        while (t--) {scanf ("%s%s", X, y);
        int A, B;
        A=strlen (x);
        B=strlen (y);
        int f=1;
            if (a==b) {if (strcmp (x, y) ==0) f=1;
        else f=0;
            } else {int i,j;
            for (i=1;i<b;i++) if (y[i]!=y[i-1]) break;
            for (j=0;j<i;j++) {if (x[j]!=y[j]) break;
            } if (j!=i) f=0;
                if (f) {int cnt=a-i; for (; i<a;i++) {for (; j<b;j++) {if (x
         [I]==y[j]) {cnt--;                   Break
                }}} if (cnt==0) f=1;
            else f=0; }} puts (F==1? ")
    Yes ":" No ");
} return 0;
 }