Identification of CIDR blocks of China Mobile Unicom and China Telecom

 

/** Determine which of the following numbers is China Unicom, China Mobile, and China Telecom,

1. * Before using this method, verify the validity rules of the number:
2. *
3. * China Mobile has 16 segments: 139,138,137,136,135,134,147,159,158,157 (3G), 151,152,150,182 (3G), 188 (3G), 187 (3G)
4. * China Unicom has the following code segments: 130,131,132,145,155,156 (3G), 186 (3G), 185 (3G), and 8 Number segments.
5. * China Telecom has the following code segments: 133,1349, 153,189 (3G), 180 (3g), and 5
6. * @ Param Mobile: number to be determined
7. * @ Return returns the corresponding type: 1 represents China Unicom; 2 represents China Mobile; 3 represents China Telecom.
8. */
9. Public String getmobiletype (string mobile ){
11. If (mobile. startswith ("0") | mobile. startswith ("+ 860 ")){
12. Mobile = Mobile. substring (mobile. indexof ("0") + 1, mobile. Length ());
13. }
14. List chinaunicom = arrays. aslist (New String [] {"130", "131", "132 ",
15. "145", "155", "156", "186", "185 "});
16. List chinamobile1 = arrays. aslist (New String [] {"135", "136", "137 ",
17. "138", "139", "147", "150", "151", "152", "157", "158", "159", "182 ", "187 ",
18. "188 "});
19. List chinamobile2 = arrays. aslist (New String [] {"1340", "1341 ",
20. "1342", "1343", "1344", "1345", "1346", "1347", "1348 "});
22. Boolean bolchinaunicom = (chinaunicom. Contains (mobile. substring (0, 3 )));
23. Boolean bolchinamobile1 = (chinamobile1
24. . Contains (mobile. substring (0, 3 )));
25. Boolean bolchinamobile2 = (chinamobile2
26. . Contains (mobile. substring (0, 4 )));
27. If (bolchinaunicom)
28. Return "1"; // China Unicom
    
29. If (bolchinamobile1 | bolchinamobile2)
30. Return "2"; // move
    
31. Return "3"; // others are Telecom
    
33. }