Today, I saw a very interesting post on Stackexchange, about how to implement 2 + 2 = 5 in various programming languages, how can 2 + 2 be equal to 5? I was puzzled at first, but I was shocked to see how the following various programming languages were implemented, and once again I believed that human beings were truly an incredible creature. 1. JAVA
Import Java.lang.reflect.Field;
public class Main {
public static void Main (string[] args) throws Exception {
Class cache = Integer.class.getDeclaredClasses () [0];
Field C = Cache.getdeclaredfield ("cache");
C.setaccessible (TRUE);
integer[] Array = (integer[]) c.get (cache);
ARRAY[132] = array[133];
System.out.printf ("%d", 2 + 2);
}
}
Output:
5
2, C
int main () {
Char __func_version__[] = "5″; For source control
Char b[]= "2″, a=2;
printf ("%d +%s =%s\n", A, b, a+b);
return 0;
}
3, C (Linux, gcc 4.7.3)
#include <stdio.h>
int main (void)
{
int a=3, b=2;
printf ("%d +%d =%d", –a, B, a+b);
}
4. Haskell
Λ> Let 2+2=5 inch
5
5. BBC BASIC
MODE 6
VDU 23,52,254,192,252,6,6,198,124,0
PRINT
PRINT "2+2=";
PRINT "2+3="; 2+3
6. Python
>>> patch = ' \x312\x2d7′
>>> Import ctypes;ctypes.c_int8.from_address (len (patch)) +8). Value=eval (Patch)
>>> 2 + 2
5
7. JavaScript
g = function () {
H = 3
Return H + H
}
f = function () {
Η= 2
returnη+ H
}
3 + 3 = 6
Alert (g ())
2 + 2 = 5
Alert (f ())
8. Bash
v=2 #v is 2
v+=2 #v is 4
v=$ (($v)) #v is 20
v=$ (($v -16)) #v is 4
v=$ (bc<<< "sqrt ($v) +2″) #v is 4 (sqrt (4) is 2)
v=$ (bc<<< "$v/4+3″) #v is 4 (4/4 = 1)
Echo ' 2+2= ' $v #So v is 4 ...?
9. PHP
Echo ' 2 + 2 = '. (2 + 2 = = = 4? 4:2 + 2 = = = 5? 5: ' Dunno ');
10. Perl
# Generic includes
Use strict;
Use warnings;
Use 5.010;
Use Acme::newmath;
# Ok, time to begin the real program.
if (2 + 2 = = 5) {
Say 5;
}
else {
Say "Dunno ...";
}
11. C #
static void Main (string[] args)
{
var x = 2;
var y = 2;
if (1 = = 0);
{
++x;
}
Console.WriteLine (x + y);
}
12. C + +
#include <iostream>
Class Int
{
Public
Int (const int& a): Integ (a) {}
Friend std::ostream& operator<< (std::ostream& oss, const int& RHS)
{
return OSS << Rhs.integ;
}
int operator+ (int o)
{
if (Integ = = 2 && O.integ = = 2)
return integ+o.integ+1;
return integ+o.integ;
}
Private
int integ;
};
int main ()
{
INT: 2;
Std::cout << both << "+" << "<<" = "<<" + ";
}
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