Io obtains the file path and Extension (Demo is provided)

This demo mainly involves obtaining the file name, directory, extension, and merging the two characters into the path. csdn's question about getting the directory at the specified layer
Http://topic.csdn.net/u/20100201/17/958c272f-2ab7-46c2-9592-afef1ec0ea28.html)

Demo download: http://pan.baidu.com/share/link? Consumer id = 446013 & UK = 3627406265
Main Application Methods:
1. getextension: Get the extension of the specified path string
2. getpathroot: Get the root directory of the specified path string
3. getfilename: get the file name and extension of the specified string
4. getfilenamewithoutextension: returns the file name of a specified path string without an extension.
5. getdirectoryname: Get the directory information of the specified path string
5. Combine: merge two path strings
The following code

Private void btngetfullfilename_click (Object sender, eventargs e) {string Path = cbopath. text; string filename = txtfilename. text; // do not use the combine solution // If (path. endswith (@ "\") // {// label3.text = path + filename; //} // else // {// label3.text = path + "\" + filename; //} // combine: combine two path strings label9.text = path. combine (path, filename);} private void btnparentpath_click (Object sender, eventargs e) {directoryinfo di = New directoryinfo (cbopath. Text); If (Di. parent! = NULL) {label9.text = di. parent. fullname;} else {label9.text = "already the root directory";} // do not use the parent solution // string Path = cbopath. text; // If (path. endswith (@ "\") // {// Path = path. substring (0, path. length-1); // label3.text = path. substring (0, path. lastindexof (@ "\") + 1); //} // else // {// label3.text = path. substring (0, path. lastindexof (@ "\") + 1); //} private void button#click (Object sender, eventargs e) {string STR = @ "C: \ Documents and Settings \ ty \ Desktop \ Engineering Test \ tttttttt \ KKK \ vv.txt "; // After the string is separated by" \ ", the length is-6, that is, the sixth item from the back to the front, the file name occupies one item, and the sixth item is actually the fifth-level directory label11.text = Str. split ('\') [Str. split ('\\'). length-6];}

 

The running result is as follows: